Answer:
1. 37.8J
2. 18 Billion Joules, 18 Gigajoules
3. 9.81 Billion Joules, 9.81 Gigajoules
Explanation:
Use the formulas provided,
KE=(1/2)mv^2 and PE=mgh, noting that g=9.81
Answer:
The final velocity of the object is,
= 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object,
= 0 m
The final displacement of the object,
= 0.75 m
The initial velocity of the object will be,
= o m/s
The final velocity of the object,
= ?
The average velocity of the object,
v = (
-
)/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is,
= 27 m/s
Question 2 is because the passengers have inertia, which is a tendency to resist change in motion
Time= 20 minutes= 20*60=1200 s
Charge=current*time=12*1200=14400 C
Answer:
Explanation:
According to the <u>Third Kepler’s Law</u> of Planetary motion:
(1)
Where;:
is the period of the satellite
is the Gravitational Constant and its value is
is the mass of the Earth
is the semimajor axis of the orbit the satllite describes around the Earth (as we know it is a circular orbit, the semimajor axis is equal to the radius of the orbit).
On the other hand, the orbital velocity
is given by:
(2)
Now, from (1) we can find
, in order to substitute this value in (2):
(3)
(4)
(5)
Substituting (5) in (2):
(6)
(7) This is the speed at which the satellite travels