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DENIUS [597]
3 years ago
5

how does the composition of a mixture of hydrogen and oxygen differ of hydrogen and oxygen differ from the composition of a comp

ound containing hydrogen and oxygen
Physics
1 answer:
mafiozo [28]3 years ago
6 0
In a mixture, there will be a solute and solvent. The hydrogen and oxygen are still two different atoms that just mixed together. But in a compound, the hydrogen and oxygen have a bond, making a new and bigger molecule. A mixture can easily be separated by physical means but a compound isn't.
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Which of acceleration, age, speed, temperature, and velocity are vector quantities?.
ollegr [7]

Velocity and acceleration are vector quantities whereas speed, temperature and age are not.

<h3>What is a vector quantity?</h3>

Vector is a quantity that has both magnitude and direction and is represented by an arrow whose direction is same as that of the quantity and length is proportional to the quantity's magnitude.

Vector has magnitude and direction but it does not have position. Velocity and acceleration both are vector quantities as they have magnitude and direction.

If the speed of an object remains same but direction changes then the object is accelerating. It is important to remember that acceleration and velocity aren't always in the same direction.

To know more about vector quantity, refer

brainly.com/question/626479

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4 0
9 months ago
A robot that can move a hand left and right and rotate the hand 360º is said to have
Luda [366]

You've described two (2) axes of motion.
The third one would have been up-and-down.
 
3 0
2 years ago
Two convex lenses are placed 15 cm apart. The left lens has a focal length of 10 cm, and the right lens a focal length of 5 cm.
Minchanka [31]

Answer:

The image distance from right lens is 2.86 cm and image is real.

Explanation:

Given that,

Focal length of left lens = 10 cm

Focal length of right lens = 5 cm

Distance between the lenses d= 15 cm

Object distance = 50 cm

We need to calculate the image distance from left lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-50}

\dfrac{1}{v}=\dfrac{3}{25}

v=8.33\ cm

We need to calculate the image distance from right lens

The object distance will be

u = 15-8.33 = 6.67\ cm

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{5}-\dfrac{1}{-6.67}

\dfrac{1}{v}=\dfrac{1167}{3335}

v=2.86\ cm

The image is real.

Hence, The image distance from right lens is 2.86 cm and image is real.

4 0
3 years ago
A 1400 kg car is moving at 12 m/s when the driver stops a car what increase in the thermal energy of the car and it surroundings
butalik [34]
KE = 1/2 mv^2

in this case, the initial kinetic energy which is converted to heat is 

KE = 1/2 1400 (12)^2

KE = 100,800 J
5 0
3 years ago
Read 2 more answers
Tuklasin
alukav5142 [94]

Answer:

Gamit ang graphic organizer na concept po punan niyo po ang mga sangay na ito at magpapakita ng paggalang sa kapwa kalaro

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2 years ago
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