(Atwood’s Machine): Two masses, 9 kg and 12 kg, are attached by a lightweight cord and suspended over a frictionless pulley. Whe
n released, find the acceleration of the system and the tension in the cord.
2 answers:
Answer:
The acceleration of the system is 1.401 m/s² and
The tension in the cord is 100.902 N
Explanation:
Let the 9 kg mass be m
Let the 12 kg mass be M
By Newton's second law of motion we have
For the 9 kg mass, T - mg = ma and for the 12 kg mass we have T - Mg = -Ma
Here we took the upward acceleration as positive a of the 9 kg mass and the downward acceleration of the 12 kg mass as -a
Solving for T for the 9 kg mass we have
T = mg + ma
Substituting the value of T in to the 12 kg mass equation, we have
mg + ma - Mg = -Ma or a = therefore the acceleration is
1.401 m/s²
and the tension is T = mg + ma = 9×(9.81+1.401) = 100.902 N
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Explanation:
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