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WINSTONCH [101]
4 years ago
13

In a wet cell battery what is the electrolyte? copper liquid acid zinc

Physics
2 answers:
Anvisha [2.4K]4 years ago
6 0

Answer:

Liquid Acid

Explanation:

The wet cell battery implies that it has an liquid inside.

The Copper and the Zinc are also the  compounts that will react in the battery as the semi-reactions implies:

Cu2+(aq) + 2e- --> Cu0

Zn2+(aq) + 2e- --> Zn0

The electrolyte is a substance present in the battery that will help the electricity to flow to the ion of interest and will not participate in the reaction, the acid should work as the electrolyte in this case.

Andrews [41]4 years ago
5 0

Answer:

the liquid acid

Explanation:

This because electrolytes are supposed to be in a liquid form.

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We do not feel the gravitational forces from objects other than the Earth because they are weak.
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A car has a mass of 1.00x10 to the 3rd power kilograms, it has an acceleration of 4.5 meters/seconds, what is the net force on t
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Explanation:

Net force on the car= mass of the car × acceleration

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3 years ago
A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
Olegator [25]

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

E_{A}=E_{B}

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

E_{B}=m*g*h+\frac{1}{2}*m*v^{2}

Therefore we will have the following equation:

(6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s]

The kinetic energy can be easily calculated by means of the kinetic energy equation.

KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J]

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s]

5 0
4 years ago
it takes car 1 minute to go from rest to 30 m/s east. What is the acceleration of this car? Please Show Work.
ivann1987 [24]
30-0 ÷ 60 = .5m/s²

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4 years ago
If 230 W of power is produced in 10 seconds, how much work is done?
liq [111]

Answer:

Hello There!!

Explanation:

Use this equation:Work done = Force x Distance.

Work done=230W×10s

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hope this helps,have a great day!!

~Pinky~

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