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jenyasd209 [6]
3 years ago
7

A situation that restricts something

Physics
1 answer:
Ostrovityanka [42]3 years ago
7 0
Answer:

Laws

Explanation:
i don’t have one but i hope ur doing well during this quarantine
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3 years ago
A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the tables edge in the
GREYUIT [131]

A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,

  • t= 0.45 seconds.
  • V=2.22m/s
  • VT=4.95 m/s

This is further explained below.

<h3>What is its speed when it hits the floor...?</h3>

Generally, the equation for motion is mathematically given as

S= ut + 0.5at²

Therefore

y = Voy t + 0.5gt^2

1 = 0.5x 98 x 6²

1=4.9t^2

t=\sqrt{0.2041 }

t= 0.45 seconds.

b) Horizontal motions are uniform.

V=Horizontal displacement/time

V=1/0.45

V=2.22m/s

C)

Vx: 2.22 m/s At bottom,

Vy² = Voy² + 2as

Vy² = 2x95x1

Vy² = 19.6

Total velocity

VT=\sqrt{( 2.22 m/)^2+19.6}

VT=4.95 m/s

Read more about  Arithmetic

brainly.com/question/22568180

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4 0
2 years ago
Times will the kinetic one
mixer [17]

Answer:

The new kinetic energy is 9 times of the initial kinetic energy.

Explanation:

The kinetic energy of an object is given by the formula as follows :

E=\dfrac{1}{2}mv^2

Where

m is mass and v is speed of the body

If the speed of the body is tripled. Let v' is the new speed, v' = 3v. The new kinetic energy is E' and it is given by :

E'=\dfrac{1}{2}mv'^2\\\\\text{Put v' = 3v}\\\\E'=\dfrac{1}{2}m\times (3v)^2\\\\=\dfrac{1}{2}m\times 9v^2\\\\=9\times (\dfrac{1}{2}mv^2)\\\\E'=9\times E

Hence, the new kinetic energy is 9 times of the initial kinetic energy.

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The seafloor spreading process at ridges produces what kind of faults?
irga5000 [103]
Active transform faults are between two tectonic<span> structures or faults.</span>
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3 years ago
Which is a unit to measure air pressure?
nata0808 [166]

Answer:

c) cubic centimetre is it's answer..

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