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Strike441 [17]
3 years ago
11

A slice of cheese has a mass of 21 g and a volume of 15 cm3. What is the density of the cheese in units of g/cm3 and g/mL?

Chemistry
1 answer:
photoshop1234 [79]3 years ago
5 0

Explanation:

First, you have to know the definition of density. Density is mass per unit volume, or D = m/V. In this problem, you are given the mass = 37 g and you are given the volume of 21 cm3. So, the density is simply m/V = 37g/21cm3 = 1.76g/cm3. It's that simple.

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If the frequency of the photon increases what happens to the wavelength and energy?
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The energy<span> per </span>photon<span> is proportional to the </span>frequency<span> of the radiation when considered as waves, ie inversely proportional to the </span>wavelength. Double the wavelength<span>, halve the </span>photon energy<span>. This means that long </span>wavelength<span> radiation (radio waves) has low </span>photon energy<span> and so does not penetrate matter.</span>
8 0
3 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
What tools would you use to measure the density of a rectangular block?
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A scale and a ruler. The scale to measure the mass, and a ruler to measure the volume.
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3 years ago
One important sugar that results from photosynthesis is cellulose. True or false
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3 years ago
A small cylinder of helium gas used for filling balloons has a volume of 2.20 L and a pressure of 14300 kPa at 25 ∘C. Part A How
Korvikt [17]

Answer:

You can fill 212 balloons.

Explanation:

First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>

  • P =  14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
  • V = 2.20 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • n = 12.70 mol

Then we <u>calculate the number of moles that can fit in a single balloon</u>:

  • 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
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Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:

  • 12.70 mol / 0.0599 mol = 212.09

So the answer is that you can fill 212 balloons.

7 0
2 years ago
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