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Strike441 [17]
3 years ago
11

A slice of cheese has a mass of 21 g and a volume of 15 cm3. What is the density of the cheese in units of g/cm3 and g/mL?

Chemistry
1 answer:
photoshop1234 [79]3 years ago
5 0

Explanation:

First, you have to know the definition of density. Density is mass per unit volume, or D = m/V. In this problem, you are given the mass = 37 g and you are given the volume of 21 cm3. So, the density is simply m/V = 37g/21cm3 = 1.76g/cm3. It's that simple.

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Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

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\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

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m = molality of the sample

i = van't Hoff factor

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i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

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8 0
2 years ago
17. Which of the following is NOT an empirical formula? *
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Answer: 17) d. C_2H_6

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Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

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To calculate the molecular formula, we need to find the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{molecular mass}}{\text{empirical mass}}

The empirical mass can be calculated from empirical formula and molar mass must be known.

17. Thus the empirical formula of C_2H_6 should be CH_3

18. The molecular formula will either be same as empirical formula or is a whole number multiple of empirical formula. Thus the empirical formula of a compound can never be twice the molecular formula.

3 0
3 years ago
Read 2 more answers
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