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Inga [223]
3 years ago
6

What is carbon fixation?

Chemistry
1 answer:
Crazy boy [7]3 years ago
7 0
Conversion process of non-organic carbon dioxide into organic compounds by living organisms.


Example: Photosynthesis
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Determine the chemical formulas for the two compounds below. (Carbon, Hydrogen, and Oxygen).
tester [92]
Remember that any intersection of lines is a C, and that the number of hydrogens attached are the necessary to complet the 4 bonds.

1) CH3 - CH (OH) - CH (CH3) -CH3

2) CH3 - O - CH(CH3)-CH2 - CH3

I have used the parenthesis to indicate that the radical inside is in other branch, bonded by a single line -
4 0
3 years ago
Determine how many moles are present in 0.23kg of SO(2)
Rama09 [41]

Answer:

3.59 moles

Explanation:

Hopefully this helps! :)

Mark as brainliest if right!

6 0
3 years ago
6547.9 feet to meters<br> Using dimensional analysis
ELEN [110]

Answer:

92.964

Explanation:

8 0
3 years ago
For the reaction: 2H2O2 --&gt; 2H2 + 2O2, what is the total number of moles of O2 produced from the complete decomposition of 8
Softa [21]
2 H₂O₂ --> 2 H₂ + 2 O₂

2 moles H₂O₂ ------> 2 moles O₂
8 moles H₂O₂ ------> ?

moles O₂ = 8 x 2 / 2

moles O₂ = 16 / 2

= 8 moles

Answer C

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4 0
2 years ago
2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo
riadik2000 [5.3K]

Answer : The value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

2NO+O_2\rightarrow 2NO_2

Rate law expression for the reaction is:

\text{Rate}=k[NO]^a[O_2]^b

As per question,

a = order with respect to NO  = 2

b = order with respect to O_2 = 1

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = 9.87\times 10^3M^{-2}s^{-1}

[NO] = concentration of NO = 7.86\times 10^{-3}M

[O_2] = concentration of O_2= 2.21\times 10^{-3}M

Now put all the given values in the above expression, we get:

\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1

\text{Rate}=1.35\times 10^{-8}Ms^{-1}

Hence, the value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

7 0
2 years ago
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