Have you ever visited an amusement park and taken a ride on a parachute drop ride? These types of rides take the passengers to a
great height, and then drop them in free fall. Before they hit the ground, the ride is slowed using a Lenz’s law mechanism thus avoiding certain death. For this discussion, first locate a photo of one of these rides (either one you’ve personally experienced or one you might like to try someday), and in your initial post, upload the photo and respond to the following:
a. Explain how Lenz’s law applies to this situation.
b. Why is the Lenz’s law mechanism ideal for such a use?
c. What other mechanisms can be used to slow the descent? Compare and contrast these options with the Lenz’s law mechanism.
Finally, be sure to respond to at least two of your peers’ discussion posts.
a. Explain how Lenz’s law applies to this situation.
b. Why is the Lenz’s law mechanism ideal for such a use?
c. What other mechanisms can be used to slow the descent? Compare and contrast these options with the Lenz’s law mechanism.
Finally, be sure to respond to at least two of your peers’ discussion posts.
1 answer:
Answer & Explanation:
a)
Lenz's law states that the direction of induced electric current is always such that, it opposes the change in magnetic flux.
In a drop ride, the hub on which we sit and are hung to is an electromagnet and there are many such magnets mounted on the columns of the support. what happens is these electromagnets (in support) generate a repulsive magnetic field with respect to the field generated by the hub solenoids. this results in lift generation till the top of ride. reaching the top, the bar solenoids are at their maximum repulsive force. Then the solenoids in column are set current less means electric supply is cut off. this makes you fall under the effect of gravity. by the time you are half way down, column solenoids are turned on again. As the hub solenoid approaches every single electromagnet in supporting columns. Due to change in magnetic field (with respect to lenz's law) an opposing current induces further providing resistance to the fall, this continues until the ride comes to rest completely. This is how it works.
c) In addition, highly compressive springs, dampers, viscous dampers, etc. could be used in its place.
but the above listed cannot provide a differential braking,
have a limited lifecycle,
will provide resistance during lift also,
require higher maintenance
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Answer: 2561.7 pounds
Explanation:
If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:
(1)
Where:
is the slope of the line
is the airplane weight with 51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)
is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)
This means we already have one point of the graph, which coordinate is:
Rewritting (1):
(2)
As Y is a function of X:
(3)
Substituting the known values:
(4)
(5)
(6)
Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):
(7)
(8) This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.