Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s. Then the mass m is 0.625kg.
Explanation: To find the answer, we need to know more about the simple harmonic motion.
<h3>
What is simple harmonic motion?</h3>
- A particle is said to execute SHM, if it moves to and fro about the mean position under the action of restoring force.
- We have the equation of time period of a SHM as,
- Where, m is the mass of the body and k is the spring constant.
<h3>How to solve the problem?</h3>
- We have to find the value of m,
Thus, we can conclude that, the mass m will be 0.625kg.
Learn more about simple harmonic motion here:
brainly.com/question/28045110
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<h2>Answers:</h2><h2 /><h2>a) Arrow B</h2><h2>b) Arrow E</h2>
Explanation:
Refraction is a phenomenon in which a wave (the light in this case) bends or changes its direction <u>when passing through a medium with a refractive index different from the other medium.</u> Where the Refractive index is a number that describes how fast light propagates through a medium or material.
According to this, if we observe the rays A an D passing throgh the biconcave lens, we will have two mediums:
1) The air
2)The material of the biconcave lens
This two mediums have different refractive indexes, hence the rays will change the direction.
-For the incident ray A, the corresponding refractive ray is B, because is the ray that bends after passing throgh the lens
-For the incident ray D, the refracted ray is E following the same principle.
Two major characteristics that change when air is heated and cooled is the density and the direction of the air flow. They change the movement of the air by heated air rises and cooled air doesn't.
Answer:
b) 2ft/s
Explanation:
A scalar has only magintude, not direction
6.2m, 3kg, and -100 o C are all scalars because they only have magnitude.
2ft/s is not a scalar because it has a direction.
Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:
Now, we will calculate the force on the piston due to atmospheric pressure:
Now, for the compression of the spring we will use Hooke's Law as follows:
where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
<u>x = 0.0734 m = 7.34 cm</u>
