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lisov135 [29]
3 years ago
15

An osprey's call is a distinct whistle at 2200 Hz. An osprey calls while diving at you, to drive you away from her nest. You hea

r the call at 2300 Hz. How fast is the osprey approaching?
I have tried this eqaution and the answer is still not correct..
vs= f+ - f-/f+ + f- (v) 2300-2200/2300+2200(343 m/s) =7.6 m/s. That is way too fast for a bird to fly? Can someone please help??
Physics
1 answer:
Elis [28]3 years ago
4 0

Answer:

14.9 m /s

Explanation:

n = n° x v /[ v -v (s) ]

n is apparent frequency , n° is source frequency,v is speed of sound and v(s)

speed of source.

2300 = 2200 x 343 / [343 -v(s)]

v (s ) = 14.9 m /s.

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A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
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Answer:

2.28

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Where f = focal length of the mirror, v = image distance, u = object distance.

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make v the subject of the equation,

v = fu/(u-f)............ Equation 2

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