<span>Answer:
Mass % KCL:
Add the grams of both compounds (31.0 g KCL + 225 g water) to find total mass and then divide the grams of KCL over the total mass, then multiply by 100: ( 31.0 g KCL / 31.0 g + 225 G) * 100%
Mole fraction KCL
Calculate the moles of KCL and water and add them to find the total moles (Moles of KCL + moles of water). Then, divide the number of KCL moles over the total moles.
moles of KCL/ moles kcl + moles water= mole fraction of KCL</span>
Volume = 0.50 L
Molar mass KBr = 119.002 g/mol
Molarity = 0.125 M
Mass ( KBr) = ?
mass = molarity * molar mass * volume
mass = 0.125 * 119.002 * 0.50
mass = 7.437625 g of KBr
hope this helps!
Yes it is a exothermic reaction.
Answer:
16.9 mmoles are needed to add to the solution
Explanation:
To solve this, we can apply the Henderson Hasselbach equation:
Acetic acid → CH₃COOH
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
That is the acid base equilibrium, to determine the amount:
pKa of acetic acid is 4.74
Henderson Hasselbach formula is:
pH = pKa + log (base/acid)
We replace → 4.97 = 4.74 + log (B / 10mmoles)
Let's verify mmoles of B
4.97 - 4.74 = log (B/10)
0.23 = log (B/10)
10^(0.23) = 10^(log (B/10)
1.698 = B/10
B = 1.698 . 10 → 16.9 mmoles