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Fittoniya [83]
4 years ago
12

Trisha and her lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In o

ne experiment, they added a piece of magnesium ribbon to 10 milliliters of hydrochloric acid. They observed bubbles being produced and did a variety of tests to identify the escaping gas; it proved to be hydrogen The reaction is represented by the following equation: Mg + 2HCl → MgCl2 + H2(g) Trisha and her lab partner filled a beaker with 150 milliliters of a 0.10 M HCl solution. How many moles of HCl are in the beaker? Remember, molarity = moles liter . A) 0.015 mol HCl B) 0.150 mol HCl C) 6.67 mol HCl D) 15 mol HCl
Chemistry
1 answer:
GaryK [48]4 years ago
7 0

<u>Given:</u>

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

<u>To determine:</u>

The # moles of HCl

<u>Explanation:</u>

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles

Ans: A)

Moles of HCl is 0.015

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<span>Answer: Mass % KCL: Add the grams of both compounds (31.0 g KCL + 225 g water) to find total mass and then divide the grams of KCL over the total mass, then multiply by 100: ( 31.0 g KCL / 31.0 g + 225 G) * 100% Mole fraction KCL Calculate the moles of KCL and water and add them to find the total moles (Moles of KCL + moles of water). Then, divide the number of KCL moles over the total moles. moles of KCL/ moles kcl + moles water= mole fraction of KCL</span>
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3 years ago
how much potassium bromide, in grams, should be added to water to prepare 0.50 of solution with molarity of 0.125M?
Flura [38]
Volume = 0.50 L

Molar mass  KBr = 119.002 g/mol

Molarity = 0.125 M

Mass ( KBr) = ?

 mass = molarity * molar mass * volume

mass = 0.125 * 119.002 * 0.50

mass = 7.437625 g of KBr

hope this helps!
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Answer:

D. potential

Explanation:

D. potential

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Is a burning log an exothermic or endothermic event if the log is the system?
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You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of
motikmotik

Answer:

16.9 mmoles are needed to add to the solution

Explanation:

To solve this, we can apply the Henderson Hasselbach equation:

Acetic acid → CH₃COOH

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻   +  H₃O⁺             Ka

That is the acid base equilibrium, to determine the amount:

pKa of acetic acid is 4.74

Henderson Hasselbach formula is:

pH = pKa + log (base/acid)

We replace  →  4.97 = 4.74 + log (B / 10mmoles)

Let's verify mmoles of B

4.97 - 4.74 = log (B/10)

0.23 =  log (B/10)

10^(0.23) = 10^(log (B/10)

1.698 = B/10

B = 1.698 . 10 → 16.9 mmoles

5 0
3 years ago
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