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Klio2033 [76]
3 years ago
7

Consider an amphoteric hydroxide, M ( OH ) 2 ( s ) , where M is a generic metal. M ( OH ) 2 ( s ) − ⇀ ↽ − M 2 + ( aq ) + 2 OH −

( aq ) K s p = 3 × 10 − 16 M ( OH ) 2 ( s ) + 2 OH − ( aq ) − ⇀ ↽ − [ M ( OH ) 4 ] 2 − ( aq ) K f = 0.04 Estimate the solubility of M ( OH ) 2 in a solution buffered at pH = 7.0, 10.0, and 14.0.
Chemistry
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

1(374€×737€÷63718477284™>)2638185837+2737=12837

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Answer:

when it reduces heat.

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What is the chemical equation for diphosphorus trioxide + water ---> phosphorous acid?
Dmitriy789 [7]
Your answer is P_{2}O_{3}+3H_{2}O\rightarrow\ 2H_{3}PO_{3}

but if you are looking for some explanation check description below :)

Diphosphorus trioxide formula is:

P_{2}O_{3}

Di stands from 2 atoms of something, in this case we have 2 atoms of Phosphorus.

Trioxide means that we have 3 atoms of oxygen in this substance that's why we have: P_{2}O_{3}

And water is just H_{2}O

Unbalanced formula is:

P_{2}O_{3}+H_{2}O\rightarrow\ H_{3}PO_{3}

Now we need to balance this equation

On left hand side we have 2 atoms of Phosphorus, on right hand side we have just one atom of Phosphorus, that's why we need to put 2 before H_{3}PO_{3}

Now we need to count all atoms of oxygen and hydrogen and make it equal on both side.

So we need to put 3 on left hand side before water to make this equation balanced.
That's why correct answer is:
P_{2}O_{3}+3H_{2}O\rightarrow\2H_{3}PO_{3}
6 0
3 years ago
According to the following reaction, how many moles of chlorine gas are necessary to form 0.739 moles carbon tetrachloride? carb
Ilia_Sergeevich [38]

Answer:

2.956 moles chlorine gas will be produced

Explanation:

Step 1: data given

Number of moles carbon tetrachloride (CCl4) = 0.739 moles

carbon disulfide (s) = CS2(s)

chlorine (g) = Cl2(g)

carbon tetrachloride (l) = CCl4(l)

sulfur dichloride (s) = SCl2 (s)

Step 2: The balanced equation

CS2(s) + 4Cl2(g) → CCl4(l) +2SCl2

Step 3: Calculate moles chlorine gas

For 1 moles Cs2 we need 4 moles Cl2 to produce 1 mol CCl4 and 2 moles SCl2

For 0.739 moles CCl4 we need 4*0.739 = 2.956 moles Cl2

2.956 moles of chlorine gas will be produced

4 0
3 years ago
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