Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
Hurricanes derive their energy from the Latent heat of condensation.
Hence, Option (1) is correct answer.
<h3>What is Latent Heat ? </h3>
The heat that is released or absorbed during a phase change of a substance is known as Latent heat.
<h3>What is Hurricanes ?</h3>
Hurricanes is basically a type of storm called a tropical cyclone. These are intense low pressure areas. Hurricanes derive their energy from the latent heat of CONDENSATION.
Thus from the above conclusion we can say that Hurricanes derive their energy from the Latent heat of condensation.
Hence, Option (1) is correct answer.
Learn more about the Latent heat here: brainly.com/question/5401454
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<span> POCl3 is the correct way to write the chemical formula for this compound</span>
Answer:
NaOH
Explanation:
Look at charge Na has +1 charge and Ca has +2 charge after dissociation . Greater charge Stronger lattice. And as we need weak Lattice, so NaoH is stronger base than Ca(OH)2.
B
. They are large and occur at shallow depths near the where the plates diverge.