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poizon [28]
3 years ago
11

How many moles of Ag will be produced from 16g of Cu, assuming AgNO3 is available in excess

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

Assuming the reaction you are referring to is the following:

AgNO3 + Cu --> Cu(NO3)2 + Ag

First, we should balance the reaction:

2 AgNO3 + Cu --> Cu(NO3)2 + 2 Ag

Now we carry out dimensional analysis, taking into account the molar ratios of different species as given in the balanced reaction and molar masses (which we can look up in the periodic table).

We begin with what we know, which is that we have 16.0 g Cu reacting and work our way toward the quantity that we would like to calculate, namely moles of Ag.

16.0 g Cu x   1 mol Cu    x   2 mol Ag    = 0.504 mol Ag

                     63.5 g Cu       1 mol Cu

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Answer: N = 2.78 × 10^23 atoms

There are N = 2.78 × 10^23 atoms in 70g of Au2cl6

Completed Question:

Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits

Explanation:

Given:

Molar mass of Au2cl6 = 303.33g/mol

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Number of Atom of gold in 0.462 mole of gold is:

N = 0.462 mol × 6.022 × 10^23 atoms/mol

N = 2.78 × 10^23 atoms

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<h3>What is Latent Heat ? </h3>

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