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3 years ago

-4x^2 (3x^2 + 25x - 7)

1 answer:

6 0

In the instructions for this problem I am told to distribute -4x^2. Why?
the order of operations is the order in which to simlify
if you look inside the parenthases, all like terms have been combined so the inside of parenthasees have already been simlified
expanding the exponents won't make it any easier so we move to distriubiting (or mulitplying)
so then the next step is mulitply -4x^2 by the trinomial

In the order of operations you must do problems inside parentheses first. Why does multiplying monomials by polynomials change this? multiplying monomails by polynomials does not change this

Would the answer come out different if I did the work according to the order of operations?
no because distributing first is what you should do if you follow order of operations

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A shark swims 140 meters in 15.5 seconds what is the sharks average swimming rate in meters per second

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140/15.5 = unit rate
140/15.5 = around 9.03
Average swimming rate: 9.03 meters per second

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3 years ago

The sum of y and two, all divided by five

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3 years ago

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3 years ago

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3 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, for the y direction, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago