Answer:
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.
Explanation:
- This is an acid-base reaction which produces salt and water according to the balanced equation:
<em>2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.</em>
<em></em>
it is clear that 2.0 moles of KOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of K₂SO₄ and 2.0 moles of H₂O
The mass would still be the same 25.0 g but the volume would be bigger
In order to balance this, you have to count
each element where the elements in the reactants side and the product side
should have equal number of molecules. The balanced reaction is as follows:
KOH + H3PO4 = KH2PO4 +H2O
Answer:
The change in entropy is -1083.112 joules per kilogram-Kelvin.
Explanation:
If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (
), in joules per gram-Kelvin, by the following model:
(1)
Where:
- Mass, in kilograms.
- Specific heat of water, in joules per kilogram-Kelvin.
, 
- Initial and final temperatures of water, in Kelvin.
If we know that 
, 
, 
and 
, then the change in entropy for the entire process is:
The change in entropy is -1083.112 joules per kilogram-Kelvin.
Electron because it’s more valid than neutron
