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Whitepunk [10]
3 years ago
12

Calculate the ratio of H+ ions to OH– ions at a pH = 6. Find the concentration of H+ ions to OH– ions listed in Table B of your

Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide. Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 6. Are they the same? Why or why not? Record your explanation in Table A. What is the concentration of H+ ions at a pH = 6? mol/L What is the concentration of OH– ions at a pH = 6? mol/L What is the ratio of H+ ions to OH– ions at a pH = 6? :1
Chemistry
2 answers:
AlekseyPX3 years ago
7 0

Answer:

You must know the concept of pH of a solution and its relation to the concentration of H+ and OH- ions. pH is a measure of the substance's acidity or basicity. From the definition of Arrhenius, an acid contains an H+ while a base contains a OH- ion. From this definition, we can say that an acidic substance has a higher concentration of H+ ions. Now, I'll introduce here that pH is the value of the negative logarithm of the concentration of H+. In equation,

pH = -log[H+]

The term pOH is therefore also, pOH = -log[OH-]. Therefore, the relationship that connects the two negative logarithms is:

pH + pOH = 14

The pH scale starts from 1 being the most acidic to 14 being the most basic. The neutral pH is 7. Thus, for a pH of 7, the H+ and the OH- concentrations are equal. 

pH = 7 = -log[H+]

[H+] = 1×10⁻⁷ mol/L = [OH-]

Since the concentrations are equal, the ratio is equal to 1.

VikaD [51]3 years ago
4 0

Answer:

the anwser is 0.000001,   0.00000001,  100:1

Explanation:

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A solution contains one or more of the following ions: Ag+, Ca2+, and Co2+. Lithium bromide is added to the solution and no prec
olchik [2.2K]
<h3>Answer:</h3>

#1. Ca²⁺

# 2. Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

#3. 3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

<h3>Explanation:</h3>

The question above concerns solubility of salts or ions in water.

The solution given contains Ag+, Ca2+, and Co2+ ions.

  • In the first case, when Lithium bromide is added to the solution, there is no white precipitate formed.
  • In the second case, the addition of Lithium sulfate results in the formation of a precipitate because of the Ca²⁺ in the solution combined with the SO₃²⁻ from lithium sulfate to form an insoluble CaSO₄.
  • The net ionic equation for the reaction is;

Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

  • From the solubility rules, all sulfates are soluble except BaSO₄, CaSO₄, and PbSO₄.
  • In the third case, the addition of Lithium phosphate results in the formation of a precipitate because Ag⁺ ions in the solution combine with phosphate ions ( PO₄³⁻) from lithium phosphate to form an insoluble salt, Ag₃PO₄.
  • The net ionic equation for the reaction is;

3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

  • According to solubility rules, all phosphates are insoluble in water except Na₃PO₄, K₃PO₄, and (NH₄)₃PO₄.
6 0
2 years ago
Give two test substances that would react with each other to produce salt and water​
Mademuasel [1]

Answer:

NaOH +HCl==>Nacl+H2O

KOH+HCl==>KOH+H2O

6 0
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krek1111 [17]

Answer:

C + O2 → CO2

Explanation:

C + O2 → CO ----------------- (1)

from equ (1) on reactant side, C has 1 mole, O has 2 moles

from equ (1) on product side, C has 1 mole, O has 1 mole

Thus, to balance the equation, O should have 2 moles

C + O2 → CO2

7 0
3 years ago
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To know the density you also need to know the volume of the rock.
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The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: Reaction sequence of acetyl chl
Svetlanka [38]

If the concentration of acetyl chloride  is increased ten times the rate of reaction is increased ten times.

The conversion of acetyl chloride to methyl acetate is a substitution reaction. Recall that a substitution reaction is one in which a moiety in a molecule is replaced by another.

In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the  methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

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