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3 years ago

Select all of the transformations that could change the location of the asymptotes of a cosecant of secant

Mathematics

2 answers:

77julia77 [94]3 years ago

4 0

Answer:

phase shift and period change

Step-by-step explanation:

just did it

NISA [10]3 years ago

4 0

yes that is right it would be phase shift and period change

Step-by-step explanation:

i also have done it

You might be interested in

The coordinates of three vertices of square ABCD are A(−212,112),B(−212,−3), and C(2,112).

Lady_Fox [76]

Answer:

Step-by-step explanation:

Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.

Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).

This shape has sides that are parallel to both axes.

To calculate the perimeter we find the length of two sides.

The distance from A to B is the difference between their y-axis:

w=112-(-3)=115

The distance from A to C is the difference between their x-axis:

l=2-(-212)=215

It's evident this is not a square but a rectangle. The perimeter is

P=2w+2l=330+430

P=760

7 0

3 years ago

Help<br> help please please

Ahat [919]

Answer:

1. A

2. C

Step-by-step explanation:

I could be wrong, that's my best guess. Im so sorry if im wrong, have a good day

7 0

3 years ago

HELP PLS WILL GIVE A LOT OF POINT

sveta [45]

Answer:

large = 18 3/4 = 18.75

small = 13/2 = 6 1/2 = 6.5

Step-by-step explanation:

Let l = the weight of large boxes

s = weight of small boxes

2 large and 3 small weights 57

2l+3s = 57

6 large and 5 small wights 145

6l+5s = 145

Multiply the first equation by 3

3(2l+3s) = 57*3

6l +9s =171

Subtract the second equation

6l +9s =171

-6l -5s = -145

-----------------------

4s =26

Divide each side by 4

4s/4 = 26/4

s = 26/4 = 13/2

Substitute this into the first equation

2l +3s = 57

2l + 3(13/2) =57

Multiply by 2 to get rid of the fractions

2(2l + 3(13/2)) =57*2

4l + 39 = 114

Subtract 39 from each side

4l +39-39 = 114-39

4l =75

Divide by 4

4l/4 = 75/4

l = 75/4 = 18 3/4

7 0

3 years ago

Read 2 more answers

What is 4/5 x 3 1/8 in simplest form

Lesechka [4]

3 1/8 means 8 x 3 + 1 = 25/8

Step-by-step explanation:

4/5 x 25/8

= 4x25/5x 8

= 100/40

= 5/2

6 0

2 years ago

Which methods correctly solve for the variable n in the equation 11−n=−20? Select all that apply. First, add n to both sides. Th

Zina [86]

Answer:

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, add 20 to both sides.

Step-by-step explanation:

Given equation:

11 - n = -20

Solve for variable n

11 - n = -20

Subtract 11 from both sides

11 - n - 11 = -20 - 11

- n = - 31

Multiply both sides by -1

- n(-1) = - 31(-1)

n = 31

First, subtract 11 from both sides. Then, multiply both sides by −1.

11 - n = -20

11 -n +n = -20 + n

11 = -20 + n

11 + 20 = -20 + n +20

31 = n

First, add n to both sides. Then, add 20 to both sides.

First, subtract n from both sides. Then, multiply both sides by −20.

First, add n to both sides. Then, subtract 11 from both sides.

11 - n = -20

11 - n +n = -20 + n

11 = -20 + n

11 - 11 = -20 + n -11

Not possible

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, subtract 20 from both sides.

11 - n = -20

11 - n + n = -20 + n

11 = -20 + n

11 - 20 = -20 + n - 20

9 = n - 40

Not possible

5 0

3 years ago