Answer:
C - 11.76 N (Newtons)
Explanation:
2 steps are needed,
First find the Force being applied by the box on the surface.
F = M(a) [Force equals: mass X Acceleration (of gravity)]
You get 39.2 N of Force.
Plug in the remaining values into the equation for Frictional Force
F(f) = μ(F) [Coefficient of Friction X Force applied by the Box]
So
F(f) = 0.3(39.2) = 11.76 N (of Frictional Force)
Answer:
I.D.K but the same measure they use to judge will be used to judge them
Explanation:
Answer is 12 milesBecause yeah
Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.