3 years ago

In order to do work, the force vector must be

Physics

1 answer:

aliina [53]3 years ago

5 0

in the same direction as the displacement vector and the motion

You might be interested in

When you have a pot of water on the stove, heat is transferred to the water. Describe the behavior of the water molecules and ho

Digiron [165]

The hotter molecules become, the faster they move around. The colder they are, the more slow and lethargic they are

3 0

3 years ago

3. A particle of charge +7.5 µC is released from rest at the point x = 60 cm on an x-axis. The particle begins to move due to th

Fed [463]

Answer:

HSBC keen vs kg get it yyyyyuuy

Explanation:

hgccccxfcffgbbbbbbbbbbghhyhhhgdghcjyddhhyfdghhhfdgbxbbndgnncvbhcxgnjffccggshgdggjhddh

nnnbvvvvvggfxrugdfutdfjhyfggigftffghhjjhhjyhrdffddfvvvvvvvvvvvbbbbbbbbbvvcxccghhyhhhjjjhjnnnnnnnnnnnnnbhbfgjgfhhccccccvvjjfdbngxvncnccbnxcvbchvxxghfdgvvhhihbvhbbhhvxcgbbbcxzxvbjhcxvvbnnxvnn

3 0

3 years ago

Choose the following types of hazards below

Aleksandr [31]

Um where are the options for the answers?

6 0

3 years ago

Read 2 more answers

from the edge of the rooftop of a building, a boy thros a stone at an angle of 25 above the horizontal. The stone hits the groun

ella [17]

Answer:38.675 m/s

Explanation:

$\theta =25^{\circ}$

t=4.2 s

$R_x=105m$

Solving in x direction

$R_x=ut+\frac{1}{2}\left ( 0\right )t^2$

$105=ucos25\times 4.2$

ucos25=25

u=27.584 m/s

Initial velocity in vertical direction usin25

Let h be the height of Rooftop

$h=\left ( -usin25\right )4.2+\frac{1}{2} \left ( 9.8\right )\left ( 4.2\right )^2$

h=37.47 m

Therefore final vertical velocity is $v_{vf}^2-\left ( usin25\right )^2=2\times 9.81\times 37.47$

$v_{vf}$ =29.51 m/s

Final Resultant velocity

$V_{final}=\sqrt{29.51^2+24.99^2}$

$V_{final}=38.675 m/s$

6 0

4 years ago

A skier starts from rest at the top of a 20 degree incline and skis in a straight line to the bottom of the slope, a distance d

SSSSS [86.1K]

Answer:

Explanation:

Loss of potential energy = mgh.

h = d sin 20

= 400 sin20 = 136.8 m

Loss of potential energy = m x 9.8 x 136.8

= 1340.64 m

negative work done by friction = μ mg cosθ x d

= .2 x m x 9.8 x cos 20 x 400

= 736.72 m

Net loss of potential energy = 1340.64 m - 736.72 m

= 603.92 m

= gain of kinetic energy = 1/2 m v²

1/2 m v² = 603.92 m

v² = 1207.84

v = 34.75 m /s .

6 0

3 years ago