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3 years ago

Which of the following is a characteristic of science?

Physics

2 answers:

vfiekz [6]3 years ago

7 0

Answer:

Using controlled conditions

Explanation:

Science experiments and tests are always carried out using specific conditions and parameters. These can be pressure, temperature, volume or the close surrounding around us which determines a 'tentative' results. The environment or the surrounding in which the tests are run plays a very important role and it has large affect on the result of the experiment. Thus these scientific experiment are carried at controlled conditions to obtain the desired results.

Thus the answer is, Using controlled conditions.

Oksi-84 [34.3K]3 years ago

6 0

Answer:

C. Using controlled conditions

Explanation:

I did the quiz and B turned out to be wrong. D just doesn't make sense. Although A can be true in some experiments, it's not always the case.

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Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce

jasenka [17]

Answer:

$\lambda= 506.25 nm$

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

$y=\frac{m \lambda D}{a}$

Where:

$y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1$

Solving for λ:

$\lambda=\frac{y*a}{mD}$

Replacing the data provided by the problem:

$\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm$

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3 years ago