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Vera_Pavlovna [14]
3 years ago
15

What is the equilibrium constant of pure water at 25°C?

Chemistry
2 answers:
ANEK [815]3 years ago
6 0
The equilibrium reaction, causes the water dissociation constant, Kw, is 1.01 × 10-14<span> at 25 °C. That is because every H</span>+<span> (H</span>3O+) ion these forms accompanied by the formation of an OH-<span> ion, are the concentrations of these ions and in pure water the same thing can be calculated from </span>Kw<span>. 

HOPED THIS HELP OUT ;)



</span>
Charra [1.4K]3 years ago
5 0

Answer:The equilibrium constant of pure water is K_{eq}=1\times 10^{-14}

Explanation:

H_2O+H_2O\rightleftharpoons H_3O^++OH^-

K_{eq}=\frac{[H_3O^+][OH^-]}{[H_2O][H_2O]}

K_i=K_{eq}\times [H_2O]}=\frac{[H_3O^+][OH^-]}{[H_2O]}

K_i=\text{Ionization constant of water}

Since,the water is found to be poorly ionized ,concentration of pure water practically remains the same. So, concentration of water can be combined with K_i to give new constant known as ionic product of water that is K_w.

K_w=K_i\times [H_2O]=[H_3O^+][OH^-]

In pure water:

[H_3O^+]=1\times 10^{-7} M]=[OH^-]

K_w=1\times 10^{-14}M^2

K_w=K_{eq}=1\times 10^{-14}

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A solution is prepared by dissolving 0.23 mol of hypochlorous acid and 0.27 mol of sodium hypochlorite in water sufficient to yi
finlep [7]

Answer:

hypochlorite ion

Explanation:

The hypochlorous acid, HClO, is a weak acid with Ka = 1.36x10⁻³, when this acid is in solution with its conjugate base, ClO⁻ (From sodium hypochlorite, NaClO) a buffer is produced. When a strong acid as HCl is added, the reaction that occurs is:

HCl + ClO⁻ → HClO + Cl⁻.

Where more hypochlorous acid is produced.

That means, the HCl reacts with the hypochlorite ion present in solution

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You have 16.7 grams of hydrogen and 15.4 grams of oxygen in a synthesis rxn. Which is the limiting reagent?
sleet_krkn [62]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of hydrogen = 16.7 g

Mass of oxygen = 15.4 g

Limiting reactant = ?

Solution:

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2H₂ + O₂   →   2H₂O

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Number of moles of oxygen:

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Number of moles = 0.48 mol

Now we will compare the moles of both reactant with product,

                 

                             H₂           :          H₂O

                              2            :            2

                             8.35        :            8.35

                             O₂           :          H₂O

                               1            :            2

                             0.48        :        2×0.48 = 0.96 mol

The number of moles of water produced by oxygen are less so it will limiting reactant.

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Lead IV oxide decompose to give lead ll oxide and oxygen. Lead iv oxide is thermally unstable and it usually decomposes into oxygen and lead ll oxide when heated. Lead ll oxide is more stable than lead lV oxide.
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