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-BARSIC- [3]
3 years ago
14

1. Hay un gas con 700 milímetros de Mercurio de presión en 922 ml de volumen a 20 grados Celsius. Calcula la temperatura final a

500 mm de mercurio con 451 ml.
2. un gas ocupa un gas ocupa 205 mililitros a 20 grados centígrados y 1,05 atm. Calcule el volumen final a 60 grados centígrados y 2,4 Atmósferas de presión.
3. tenemos 22 L de un gas a una temperatura de 220 K y una presión de 5 Atm, si se modifican la presión a 6.5 atm y la temperatura a 200 K, cuál será el volumen que obtenemos.
Chemistry
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

püvinlbxyfsswgrxzvnnchcyv nkivtcdg

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Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
Colloids and suspension are described as ________ heterogeneous _________ mixtures
solong [7]

The question is already answered.

3 0
3 years ago
What is my percent yield if I calculated that a reaction would yield 20.0 g of iron (II) chloride, but I only managed to get 4.0
sergiy2304 [10]

Answer:

Theoretical yield is 20%.

Explanation:

Percent yield = [(actual yield)/(theoretical yield)]\times 100 %

Theoretical yield is calculated amount of product by using stoichiometric ratio between reactant and product.

Actual yield is the amount of product which is experimentally obtained.

Here theoretical yield is 20.0 g and actual yield is 4.0 g.

So, percent yield = \frac{4.0g}{20.0}\times 100 % = 20%

6 0
4 years ago
Calculate the molarity of the two solutions. The first solution contains 0.550 mol of NaOH in 1.40 L of solution.
olya-2409 [2.1K]

Answer:

0.393 mol/L.

Explanation:

The following data were obtained from the question:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the molarity of the NaOH solution as follow:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity = mole / Volume

Molarity of NaOH = 0.55 / 1.4

Molarity of NaOH = 0.393 mol/L

Thus, the molarity of the NaOH solution is 0.393 mol/L.

6 0
3 years ago
20 dekameters equals how many centimeters
stich3 [128]

20000 centimeters because 1 dekameter is 1000 centimeters

3 0
3 years ago
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