<h3>
Answer:</h3>
= 5.79 × 10^19 molecules
<h3>
Explanation:</h3>
The molar mass of the compound is 312 g/mol
Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)
We are required to calculate the number of molecules present
We will use the following steps;
<h3>Step 1: Calculate the number of moles of the compound </h3>

Therefore;
Moles of the compound will be;

= 9.615 × 10⁻5 mole
<h3>Step 2: Calculate the number of molecules present </h3>
Using the Avogadro's constant, 6.022 × 10^23
1 mole of a compound contains 6.022 × 10^23 molecules
Therefore;
9.615 × 10⁻5 moles of the compound will have ;
= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules
= 5.79 × 10^19 molecules
Therefore the compound contains 5.79 × 10^19 molecules
Answer - Inter-molecular attractions
Explanation-
As we know everything around us is made up of matter that means everything has molecules as their basic structure. The state of anything is decided by the spaces between the molecules.
The state of the objects that have strong inter-molecular attractions a solid and gradually the lesser will be in state of liquid and gas. The attraction between the molecules is overcome only when a certain amount of energy is provided from outside.
Answer:
It's false ok it's non electrolyte
Answer:
Carbon-14 or C-14
Explanation:
Since the isotope is a carbon isotope, it means the the atomic number of the isotope is 6.
The atomic number of an element is the proton number.
Therefore, the isotope has a proton number of 6
Now we need to obtain the mass number of isotope in order to write the symbol of the isotope. This is illustrated below:
Mass number = Proton +Neutron
Proton = 6
Neutron = 8
Mass number = 6 + 8
Mass number = 14
Therefore, the symbol of the isotope is carbon-14 or C-14