Answer: hello your question is poorly written below is the complete question
answer:
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
Explanation:
Determining the type of orbital in which the lone pair on each N atom will reside.
From the configuration attached below we can determine the type of orbital and they are ;
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
This material has a density of 1 g/cm3.
(since 12.48 g/ 12.48 cm3 = 1 g/cm3)
Therefore, this material is water.
Answer:
The coefficient that should be inserted in front of chlorine is 2
Explanation:
Sn + 2Cl₂ → SnCl₄
As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.
Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.
The law of conservation of mass must be respected in every chemical equation
The answer would be b, or 2
Maximum number of covalent bonds that an oxygen atom can make with hydrogen is 2.
- the ground state electronic configuration of oxygen is 2s² 2p⁴ that means it has 6 electrons in its valence shell and require two electrons are required to complete its octate.
- Two bonds are created when an electron donor atom shares the two needed electrons with oxygen. The ability of two oxygen atoms to share valence electrons results in the creation of a double bond between the two atoms.
- There are no longer any empty orbitals in the octet of oxygen after it is complete. As a result, it is unable to accept more electrons or create more bonds.
Therefore, Oxygen can only generate two bonds because it needs two additional electrons to complete its octet, after which it will run out of empty orbitals in which to receive additional electrons and create additional bonds.
learn more about octate here:
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