1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
2 years ago
15

If the absorbance of the 10μM solution is 0.24, what should be the absorbance of the 50μM? Write answer to two decimal places.

Chemistry
1 answer:
Phoenix [80]2 years ago
3 0
Absorbance/Concentration = Constant.

That is, absorbance is directly proportional to concentration.

Therefore,

0.24/10 = x/50, where x is the absorbance at 50 micro m.

Calculating for x;
x=50* (0.24/10) = 1.20 (correct to 2 decimal places)
You might be interested in
Help plssssssssssssssss??
ser-zykov [4K]

Answer:

Chemical properties, such as combustibility, are generally observed as the identity of a substance changes and one or more new substances form.

Explanation:

Chemical change involves formation of new substances. Therefore, the correct answer is "Chemical properties, such as combustibility, are generally observed as the identity of a substance changes and one or more new substances form."

8 0
2 years ago
Devices that mix air or oxygen with flammable gasses cannot be used unless approved by
Feliz [49]

Flammable gases are gases that have the tendency to <u>explode (burst into flames)</u> when they come in contact with the <u>appropriate quantities of air, oxygen, or any suitable oxidant.</u>

<u />

<u />

Devices that mix air or oxygen with flammable gasses cannot be used unless approved by an <u>authorized or approved personnel.</u>

<u></u>

<u></u>

  • Examples of flammable gases are hydrocarbons such as <u>Propane, Acetylene</u>, e.t.c.

  • Flammable gases are dangerous to humans and the environment and if they are not handled properly, can cause severe damages and even death.

  • During the preparation and usage of flammable gases, safety precautions should be properly enforced such as the <u>wearing of appropriate safety gear and goggles</u>.

  • Devices that mix air or oxygen with flammable gases cannot be used unless approved by an <u>authorized or approved personnel.</u>

<u></u>

<u></u>

To learn more, visit the link below:

brainly.com/question/3702349

8 0
2 years ago
4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration
anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

brainly.com/question/24201923

brainly.com/question/9779410

brainly.com/question/17030163

#SPJ1

3 0
2 years ago
How do oil spills affect marine ecosystems?
charle [14.2K]
Oil makes it impossible for fur-bearing mammals to insulate<span>, this leaves them unprotected from the harsh elements out in the water. Birds and mammals will die from hypothermia without the ability to insulate from the freezing water. 

I hope this helps you! :-)</span>
3 0
2 years ago
How many moles of ammonium nitrate will be produced 110.0g of ammonium carbonate
marshall27 [118]

Answer:

                     2.288 Moles of NH₄NO₃

Explanation:

The Balance chemical equation is as follow:

                  (NH₄)₂CO₃ + 2 HNO₃  →  2 NH₄NO₃ + H₂O + CO₂

To solve this problem we will do following steps:

Finding moles of Ammonium Carbonate:

As we know,

                        Moles  =  Mass / M.Mass

So,

                        Moles  =  110 g  /  96.08 g/mol

                        Moles  =  1.144 moles

Calculating moles of Ammonium Nitrate:

According to balance chemical equation;

                      1 mole of (NH₄)₂CO₃ produces  =  2 moles of NH₄NO₃

So,

          1.144 moles of (NH₄)₂CO₃ will produce  =  X moles of NH₄NO₃

Solving for X,

                     X =  2 moles × 1.144 moles ÷ 1 mole

                     X  =  2.288 moles of NH₄NO₃

8 0
3 years ago
Other questions:
  • Which of the following elements do you expect to be most like sulfur?
    14·2 answers
  • Which of the following reactions show a decrease in entropy? a. CaO(s) + H2O(l) Ca(OH)2 (s)
    14·2 answers
  • Evaluate (754 mm )/(43 s ) to three significant figures and express answer in si units using an appropriate prefix.
    5·1 answer
  • Which of the following correctly shows a neutralization reaction between a hydronium ion and a hydroxide ion?
    11·2 answers
  • Which of the following is least likely to increase the rate of diffusion?A small concentration gradientB higher concentration of
    14·1 answer
  • How many grams of hydrogen gas would be needed to form 8.0 grams of water
    6·1 answer
  • What is the Lewis dot diagram structure for PI2F
    13·1 answer
  • What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?
    11·2 answers
  • Explain and define the angular momentum quantum number without the internet
    9·1 answer
  • What name is given to the amount of substance in an object?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!