Question

A 86.3 μC charge has a potential of 17.5 V. Determine how much kinetic energy, in eV, this charge could have.

Answer 1

Answer:

9.44 eV

Explanation:

q = Amount of charge = 86.3 μC = 86.3 x 10⁻⁶ C     (Since 1 μC =  10⁻⁶ C)

V = Electric potential of the charge = 17.5 Volts

U = Amount of electric potential energy carried by charge

Amount of electric potential energy carried by charge is given as

U = q V

Inserting the values

U = (86.3 x 10⁻⁶) (17.5)

U = 0.00151 J

U = $\frac{0.00151}{1.6\times 10^{-19}}$

U = 9.44 eV

KE = Kinetic energy the charge could have

Using conservation of energy

KE = U

KE = 9.44 eV