Answer:
-1.09m/sec^2
Explanation:
Acceleration= (Vf-Vi)/Time
=12-54.8
= -42.8
= -42.8/39
=-1.09
-ve sign is due to recoil of train
as it suddenly hits brakes.
Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.
<h3>How is the aerobic breathing process?</h3>
Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.
In this case, Aerobic cellular respiration have 3 parts:
- Glycolysis(yeilds 2ATP & 2NADH).
- Pyruvate Oxidation(yeilds 2NADH).
- Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).
So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.
See more about Aerobic cellular respiration at brainly.com/question/22531444
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Answer:
The answer to your question is: t = 2.5 s
Explanation:
Data
vo = 30 m/s
a = -12 m/s2
t = ?
vf = 0 m/s
Formula
vf = vo + at
Substitution
0 m/s = 30 + (-12)t
Solve it for t -30 = -12t
t = -30 / -12
t = 30/12 = 15/6 = 5/2
t = 2.5 s
Answer:
5N
Explanation:
Given parameters:
Original length = 22cm
Spring constant, K = 50N/m
New length = 32cm
Unknown
Force applied = ?
Solution:
The force applied on a spring can be derived using the expression below;
Force = KE
k is the spring constant
E is the extension
extension = new length - original length
extension = 32cm - 22cm = 10cm
convert the extension from cm to m;
100cm = 1m;
10cm will give 0.1m
So;
Force = 50N/m x 0.1m = 5N
