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Montano1993 [528]
3 years ago
6

In which situation is the maximum possible work done?

Physics
1 answer:
ExtremeBDS [4]3 years ago
3 0

Answer:

Answer is A.

Explanation:

Remember the equation for work:

W = F d cos θ

Math explanation: When θ = 0, cos θ = 1, so Fd is a maximum. For any other value of θ up to 90 degrees, cos θ < 1 so Fd will be smaller. For θ = 180, you're pushing away from the direction of displacement so you're actually doing negative work.

Intuitive explanation: you have the most success pushing an object when you apply the force directly against it compared to if the force was directed at an angle.

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39. What is the change in momentum for a 5,000 kg ship in
Ivan

Answer:

Change in momentum is zero.

Explanation:

The following data were obtained from the question:

Mass (m) = 5000 kg

Time (t) = 1 h

Net force (F) = 0

Change in momentum =?

Force = Rate of change of momentum

0 = change in momentum

Change in momentum = 0

We can see from the above illustration that the net force is zero. Thus, the change in momentum is also zero.

6 0
2 years ago
Suppose you are in total equilibrium in water (in other words you are floating and not moving in any direction)What could you do
Eva8 [605]

Explanation:

According to newtons first law of motion:

'' a body will continue in its state of rest or uniform motion along a path unless it is acted upon by an external force".

A body in equilibrium that is floating will be stable and not move in any direction. Even if it moves, the motion will be constant wouldn't change.

  • To move the body in any direction, one has to swim.
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learn more:

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5 0
3 years ago
How may stars are in the sky
Veseljchak [2.6K]
Is impossible say how many stars are in the sky haha
7 0
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Prove that..<br>please help<br>​
GaryK [48]

\large{ \boxed{ \bf{ \color{red}{Universal \: law \: of \: gravitation}}}}

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.

❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.

According to universal law of gravitation,

\large{ \longrightarrow{ \rm{F \propto m_1 m_2}}}

Also,

\large{ \longrightarrow{ \rm{ F \propto  \dfrac{1}{ {d}^{2} } }}}

Combining both, We will get

\large{ \longrightarrow{ \rm{F  \propto  \dfrac{ m_1 m_2}{ {d}^{2}}}}}

Or, We can write it as,

\large{ \longrightarrow{ \rm{F  \propto  \:  G \dfrac{ m_1 m_2}{ {d}^{2} }}}}

Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.

☯️ Hence, derived !!

<u>━━━━━━━━━━━━━━━━━━━━</u>

8 0
3 years ago
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