Given what we know, we can confirm that this result from the goalie is a clear indicator of room for improvement in the reaction speed and visual coordination for this area of the net.
<h3>How can the goalie improve reaction speeds to this area?</h3>
The key for situations like this is simply repetition. The more the goalie is able to practice with shots in this area of the net, the more muscle memory they will build regarding reacting to these shots, and therefore less time will be needed to block them in the future.
Therefore, we can confirm that this result from the goalie is a clear indicator of room for improvement in the reaction speed and visual coordination for this area of the net.
To learn more about reaction speeds visit:
brainly.com/question/8186329?referrer=searchResults
<h2>
Its velocity when it crosses the finish line is 119.40 m/s</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = ?
Time, t = 6.70 s
Displacement, s = 1/4 mi = 0.25 mi = 400 m
Substituting
s = ut + 0.5 at²
400 = 0 x 6.70 + 0.5 x a x 6.70²
a = 17.82 m/s²
Now we have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = ?
Time, t = 6.7 s
Acceleration, a = 17.82 m/s²
Substituting
v = u + at
v = 0 + 17.82 x 6.7
v = 119.40 m/s
Its velocity when it crosses the finish line is 119.40 m/s
Answer:
It will require 14.715 N of force to hold the cartoon beneath the water.
Explanation:
Given the the volume of cartoon is 1.5 liters.
We need to find the force required to hold this cartoon beneath the water.
As we know from the Archimedes principle that the net force is equal to the volume of liquid displaced.
Given volume of the cartoon is 1.5 liters. So, 1.5 liters of water will be displaced.
And we know the density of the water is 
. That is 
And 
So, it will require 14.715 N of force to hold 1.5 liter volume of cartoon beneath the water.
Take a car collision as an example, the more you speed up as means of acceleration, the more force will be on impact.
