Answer is: the % ionization of hypochlorous acid is 0.14.
Balanced chemical
reaction (dissociation) of an aqueous solution of hypochlorous acid:
HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq).
Ka = [H⁺] · [ClO⁻] / [HClO].
[H⁺] is equilibrium concentration of hydrogen cations or protons.
[ClO⁻] is equilibrium concentration of hypochlorite anions.
[HClO]
is equilibrium concentration of hypochlorous acid.
Ka is the acid
dissociation constant.
Ka(HClO) = 3.0·10⁻⁸.
c(HClO) = 0.015 M.
Ka(HClO) = α² · c(HClO).
α = √(3.0·10⁻⁸ ÷ 0.015).
α = 0.0014 · 100% = 0.14%.
Answer: Bonding always involve a pair of electrons and atoms and are shared between two non metals.
Answer:
26.4 960 for the first one
8.9569 for the second one
