Question

A net force of Fnet acts on an object, causing the object to accelerate at a rat of 9m/s/s. what is the acceleration rate in a second trial, if a new net force of 2Fnet acts on the same object?
a) 3m/s/s
b) 4.5m/s/s
c) 18m/s/s
d) 81m/s/s

Answer 1

The new acceleration is c) 18m/s/s

Explanation:

Net force, mass and acceleration of an object are related by Newton's second law of motion:

$F=ma$

where

F is the net force on the object

m is its mass

a is its acceleration

In the first trial of this problem, a net force of $F_{net}$ is applied to the object, causing an acceleration of

$a=9 m/s^2$

Calling the mass of the object 'm', this means that

$F_{net} = ma = 9m$ [N] (1)

In the second trial, the force applied is $2F_{net}$, so we have

$2F_{net} = ma'$

where a' is the new acceleration. Substituting (1) into the second equation, we find:

$2(9m) = ma' \rightarrow a' = 18 m/s^2$

This is because the acceleration is directly proportional to the force applied: therefore, if the force applied doubled, the acceleration doubles as well.

Learn more about Newton's second law:

brainly.com/question/3820012

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