The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
- <em>Mass of cart 1 = m1 = 1 kg</em>
- <em>Mass of cart 2 = m2 = 2kg</em>
- <em>Force applied on cart 1 = 2 N</em>
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
Thus, the force exerted on the cart 2 during the collision is 2 N.
Learn more about Newton's third law of motion here: brainly.com/question/13874955
Answer:
(a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
Explanation:
Given that,
Power factor = 0.6
Power = 600 kVA
(a). We need to calculate the reactive power
Using formula of reactive power
...(I)
We need to calculate the
Using formula of
Put the value into the formula
Put the value of Φ in equation (I)
(b). We draw the power triangle
(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95
Using formula of reactive power
We need to calculate the difference between Q and Q'
Put the value into the formula
Hence, (a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
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Answer:
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Explanation:
Radiowaves are on the higher end of the spectrum, then infrared, visible light, and UV light (which is the lowest energy)
Answer:
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