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Answer:
Lone pairs cause bond angles to deviate away from the ideal bond angles
Explanation:
Bonded electrons are stabilized and clustered between the bonding electrons meaning they are much closer together. Non-bonding electrons however are not being shared between any atoms which allows them to roam a little further spreading the charge density over a larger space and therefore interfering with what would be an expected bond angle
Answer: he did travel 15 meters.
Explanation:
We have the data:
Acceleration = a = 1.2 m/s^2
Time lapes = 3 seconds
Initial speed = 3.2 m/s.
Then we start writing the acceleration:
a(t) = 1.2 m/s^2
now for the velocity, we integrate over time:
v(t) = (1.2 m/s^2)*t + v0
with v0 = 3.2 m/s
v(t) = (1.2 m/s^2)*t + 3.2 m/s
For the position, we integrate again.
p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0
Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m
Then the displacement at t = 3s will be equal to p(3s).
p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m
The time it takes the plane to change its velocity is 9s.
<h3>What is time?</h3>
Time can be defined the measured or measurable period during which an action, process, or condition exists or continues.
To calculate the time it takes the airplane to change its velocity, we use the formula below.
Formula:
- t = (v-u)/a.......... Equation 1
Where:
- a = Acceleration
- v = Final velocity
- u = Initial velocity
- t = time
From the question,
- v = 40 m/s
- u = 22 m/s
- a = 2 m/s²
Substitute these values into equation 1
- t = (40-22)/2
- t = 18/2
- t = 9s
Hence, the time it takes the plane to change its velocity is 9s.
Learn more about time here: brainly.com/question/2854969
-- If the object is moving with speed of 10.954 meters per second, then
it has 300J of kinetic energy no matter where it may be located.
-- If the object is 6.118 meters above somewhere, then it has 300J of
gravitational potential energy relative to that place.
