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melisa1 [442]
3 years ago
9

Suppose a movie director is filming on a set that should look like a hot desert. He wants the scene to appear warmer, so that th

e red and yellow tones are the most apparent. What color filters should be use? What color will the blue sky appear when he uses those filters, and why?
Physics
1 answer:
ddd [48]3 years ago
4 0

Based on the question above, the colour that will appear are red and yellow filters respectively.

<h3>Red colour</h3>

  • It is commonly used in landscapes. It will darken foilage, and will dramatically increase the contrast in cloudy skies.

<h3>Yellow colour</h3>

  • It has a subtle effect - will darken skin slightly.

In conclusion, we can conclude that red and yellow filters should be used.

Learn more about colour filters here: brainly.com/question/883931

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Two point charges totaling 8 μC exert a repulsive force of 0.15 N on one another when separated by 0.5 m. What is the charge on
nexus9112 [7]

Answer:

B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C

Explanation:

From Coulomb's Law the electrostatic repulsive force is given by the following formula:

F = kq₁q₂/r²

where,

F = Repulsive Force = 0.15 N

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = Magnitude of 1st Charge = ?

q₂ = Magnitude of 2nd Charge = ?

r = Distance between Charges = 0.5 m

Therefore,

0.15 N = (9 x 10⁹ N.m²/C²)q₁q₂/(0.5 m)²

q₁q₂ = (0.15 N)(0.5 m)²/(9 x 10⁹ N.m²/C²)

q₁q₂ = 4.17 x 10⁻¹²

q₁ = (4.17 x 10⁻¹²)/q₂   -------------------- equation (1)

The sum of charges is given as:

q₁ + q₂ = 8 μC

q₁ + q₂ = 8 x 10⁻⁶

using equation (1):

(4.17 x 10⁻¹²)/q₂ + q₂ = 8 x 10⁻⁶

(4.17 x 10⁻¹²) + q₂² = 8 x 10⁻⁶ q₂

q₂² - (8 x 10⁻⁶) q₂ + (4.17 x 10⁻¹²) = 0

Solving this quadratic equation:

q₂ = 7.4 x 10⁻⁶ C   (OR)   q₂ = 0.56 x 10⁻⁶ C

q₂ = 7.4 μC   (OR)   q₂ = 0.6 μC

Therefore,

q₁ = (4.17 x 10⁻¹² C)/(7.4 x 10⁻⁶ C)

q₁ = 0.6μC

Now, if we solve with q₂ = 0.6 μC, we will get q₁ = 7.4 μC.

Therefore, the correct option will be:

<u>B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C</u>

8 0
3 years ago
Is there gravity in space? If so name one piece of evidence
Eddi Din [679]
There is gravity everywhere in space. In fact, it's how the moon orbits the Earth. Also, gravity in space assists the Earth to orbit the sun. These are caused by small areas of gravity. The term for this is called "microgravity".

I hope this helps!
8 0
4 years ago
What is the charge on an object that has 1.09x10^13 excess electrons?
Nadya [2.5K]

Answer:

-1.74\cdot 10^{-6} C

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

e=-1.6\cdot 10^{-19}C

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

Q=Ne

In this problem, the number of excess electrons in the object is:

N=1.09\cdot 10^{13}

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C

5 0
4 years ago
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
4 years ago
Which parameter of glass is measured with bromoform and bromobenzene mixtures in a column?
Ahat [919]
The answer is Density.  The Density of the <span>glass is measured with bromoform and bromobenzene mixtures in a column.  </span>Density measurement<span> is done using Density gradient </span>columns. It is a <span> temperature-controlled density </span>column<span> containing a </span>mixture<span> of  b</span>romobenzene<span> and  </span>bromoform.
6 0
3 years ago
Read 2 more answers
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