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Kipish [7]
3 years ago
13

Based on reference table S, atoms of which of these elements have the strongest attraction for the electrons in a chemical bond?

Chemistry
1 answer:
pychu [463]3 years ago
4 0

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of Si is 14 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}.

Atomic number of P is 15 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}.

Atomic number of Al is 13 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}.

Atomic number of S is 16 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}.

To completely fill 3p orbital, sulfur will readily accept two electrons as it is more electronegative. Thus, by gaining two electrons it will become stable in nature.

Therefore, we can conclude that atoms of sulfur (S) will have the strongest attraction for the electrons in a chemical bond.

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If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
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CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
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