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Kipish [7]
3 years ago
13

Based on reference table S, atoms of which of these elements have the strongest attraction for the electrons in a chemical bond?

Chemistry
1 answer:
pychu [463]3 years ago
4 0

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of Si is 14 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}.

Atomic number of P is 15 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}.

Atomic number of Al is 13 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}.

Atomic number of S is 16 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}.

To completely fill 3p orbital, sulfur will readily accept two electrons as it is more electronegative. Thus, by gaining two electrons it will become stable in nature.

Therefore, we can conclude that atoms of sulfur (S) will have the strongest attraction for the electrons in a chemical bond.

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Answer:

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Explanation:

The higher is the exposed area of sugar, the faster is the dissolution process. Thus, to choose between the different types of sugar, we have to look at the volume occupied by the sugar.

In sugar cubes, the particles of sugar as compacted in a cube, so the particles inside the cube are not exposed to the solvent (water). So, sugar cubes have the slowest dissolution process. Then, in granulated sugar, the particles have more area exposed, so this type of sugar will dissolve faster than sugar cubes. Finally, powdered sugar is composed of tiny particles with more are exposed, so powdered sugar has the fastest dissolution process.

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3 years ago
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