All categories

2 years ago

Based on reference table S, atoms of which of these elements have the strongest attraction for the electrons in a chemical bond?

Chemistry

1 answer:

pychu [463]2 years ago

4 0

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of Si is 14 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}$ .

Atomic number of P is 15 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

Atomic number of Al is 13 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ .

Atomic number of S is 16 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$ .

To completely fill 3p orbital, sulfur will readily accept two electrons as it is more electronegative. Thus, by gaining two electrons it will become stable in nature.

Therefore, we can conclude that atoms of sulfur (S) will have the strongest attraction for the electrons in a chemical bond.

You might be interested in

BRAINLIESTTT !!! Pls help ASAP !!!! How does plasma state of matter interact with other matter?

Ivan

Answer:

Plasma is a state of matter in which an ionized gaseous substance becomes highly electrically conductive to the point that long-range electric and magnetic fields dominate the behaviour of the matter. The plasma state can be contrasted with the other states: solid, liquid, and gas

Explanation:

7 0

3 years ago

When work is done on an object, the amount of ________ it has changes.

arsen [322]

Hey there!

When work is done on an object, the amount of energy it has changes.

Hope this helps!

~Autumly

3 0

2 years ago

Given the partial equation:

Nikolay [14]

Answer : The balanced chemical equation in acidic medium will be,

$IO_3^-(aq)+2Sn^{2+}(aq)+6H^+(aq)\rightarrow I^-(aq)+2Sn^{4+}(aq)+3H_2O(l)$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion $(H^+)$ at that side where the less number of hydrogen are present.

Now balance the charge.

The given chemical reaction is,

$IO_3^-(aq)+Sn^{2+}(aq)\rightarrow I^-(aq)+Sn^{4+}(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-$

First balance the main element in the reaction.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-$

Now balance oxygen atom on both side.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-+3H_2O$

Now balance hydrogen atom on both side.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-+6H^+\rightarrow I^-+3H_2O$

Now balance the charge.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}+2e^-$

Reduction : $IO_3^-+6H^++4e^-\rightarrow I^-+3H_2O$

The charges are not balanced on both side of the reaction. Thus, we are multiplying oxidation reaction by 2 and the adding both equation, we get the balanced redox reaction.

Oxidation : $2Sn^{2+}\rightarrow 2Sn^{4+}+4e^-$

Reduction : $IO_3^-+6H^++4e^-\rightarrow I^-+3H_2O$

The balanced chemical equation in acidic medium will be,

$IO_3^-(aq)+2Sn^{2+}(aq)+6H^+(aq)\rightarrow I^-(aq)+2Sn^{4+}(aq)+3H_2O(l)$

5 0

2 years ago

If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog

9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

8 0

2 years ago

What words do scientist use to classify their ideas?

Nady [450]

Answer:

taxonomy

Explanation:

6 0

3 years ago