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3 years ago

Based on reference table S, atoms of which of these elements have the strongest attraction for the electrons in a chemical bond?

Chemistry

1 answer:

pychu [463]3 years ago

4 0

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of Si is 14 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}$ .

Atomic number of P is 15 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

Atomic number of Al is 13 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ .

Atomic number of S is 16 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$ .

To completely fill 3p orbital, sulfur will readily accept two electrons as it is more electronegative. Thus, by gaining two electrons it will become stable in nature.

Therefore, we can conclude that atoms of sulfur (S) will have the strongest attraction for the electrons in a chemical bond.

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ILL GIVE BRAINLIEST

Mice21 [21]

Answer:

Which of the following happens during a lunar eclipse?

Select one:

a. Earth casts a shadow on the moon.

b. The moon casts a shadow on Earth. 

c. Earth stops revolving in its orbit.

d. Earth starts revolving around the moon.

Explanation:

7 0

3 years ago

In which of these diatomic molecules would you NOT find an octet of electrons

Semmy [17]

Answer:

The hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

Explanation:

Let's evaluate each case.

1. Nitrogen (N₂):

With Z = 7, nitrogen has the following electronic configuration

1s²

2s² 2p³ → valence electrons

Since its valence electrons are 5, in the molecule one nitrogen atom shares 3 electrons with the other one, and each remains with an electron pair, so each atom has an octet of electrons.

2. Hydrogen (H₂):

With Z = 1, its electronic configuration is:

1s¹ → valence electron

In the molecule, the hydrogen atoms share the only electron they have, so they will have only 2 electrons around. In this diatomic molecule, we can not find an octet.

3. Oxygen (O₂):

Z = 8. Electronic configuration:

1s²

2s² 2p⁴ → valence electrons

In the diatomic molecule, each oxygen atom shares 2 electrons with the other one and remains with 2 pairs of electrons, therefore, each oxygen atom has an octet.

4. Fluorine (F₂)

Z = 9. Electronic configuration:

1s²

2s² 2p⁵ → valence electrons

In this molecule, each fluorine atom shares 1 electron with the other and remains with 3 pairs of electrons, hence, each fluorine atom has an octet of electrons around.

Finally, we can say that the hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

I hope it helps you!

8 0

2 years ago

Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at

kozerog [31]

Answer:

20 g/mol

Explanation:

We can use Graham’s Law of diffusion:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r = \frac{1 }{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

Squaring both sides, we get

$(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}$

Solve for M₂:

$M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}$

$M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}$

$= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}$

7 0

3 years ago

The theater student talks about a type of theater from Japan called ___________.

TiliK225 [7]

I think the correct answer would be Kabuki. It is a Japanese traditional form of theater that is characterized by the heavy make-up worn by the performers. It started during the Edo Period. It is one of the major classical theater in Japan.

8 0

3 years ago

Chemistry help. Will give Brainliest!

VashaNatasha [74]

#1. An element or ion that has lost two electrons must have a net charge of 2+, because it has two more protons than electrons, therefore the answer is Mg2+

#2. aluminum ions have an oxidation state of 3+ and fluoride has an oxidation state of 1-, therefore I’m order for the charges to cancel you need 3 fluoride ions.
Therefore, the answer is AlF3

8 0

3 years ago