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2 years ago

How to make snow ice cream without sweetened condensed milk?.

Chemistry

2 answers:

Eddi Din [679]2 years ago

6 0

Answer:

What you'll need:

Milk, snow, vanilla, salt, and sugar

You will also need the following kitchen supplies: a large mixing bowl, a medium mixing bowl, a whisk, and a spoon

Whisk to combine sugar, milk, vanilla extract, and salt.

Add 8 cups of snow (fresh clean snow!!!) to a large bowl.

Pour the milk mixture over the snow and stir to combine

Explanation: Hope this helps<3

Montano1993 [528]2 years ago

6 0

Well the cream doesnt have to be sweetened, or condensed.

One time in my FACE class (food, and consumer economics.) i made homemade icecream with cream, sugar (optional technically) vanilla (also optional, its just for flavor), and ice.

You place everything but ice in a ziplock bag, (close it) then place the ice in a different, bigger, ziplock back, and then place the small bag inside the ice bag. Close the big bag, and shake it untill you get icecream.

Explanation:

Yum? My bag popped, so i dont actually know if it tastes good. My friend liked it though.

You might be interested in

How many grams are in 1 mole of Pb3(PO4)4?

kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2 .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 . 4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0

3 years ago

Read 2 more answers

8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8

garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7) kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0

3 years ago

Please answer both questions.

Deffense [45]

Answer:

1)Krypton

2)11H

Explanation:

electrons=protons

protons=atomic number

mass number=protons+neutrons

mass number is the superscript

atomic number is the subscript.

1)The answer is Krypton because its atomic number= number of protons=number of electrons is 36.

mass number is 46+36=82.

2)subscript=atomic number=number of protons=number of electrons

i. H = electrons=1

=neutrons=0

ii. Cl=electrons=17

=neutrons=35-17=18

iii. Na=electrons=11

=neutrons=23-11= 12

so the answer is Hydrogen because it has 1 electron and 0 neutron.

I hope this helps.

6 0

3 years ago

If the percent yield for the following reaction is 75.0%, and 25.0 g of NO₂ are consumed in the reaction, how many grams of nitr

victus00 [196]

Answer:

17.1195 grams of nitric acid are produced.

Explanation:

$3NO_2+H_2O\rightarrow 2HNO_3+NO$

Moles of nitrogen dioxide :

$\frac{25.0 g}{56 g/mol}=0.5434 mol$

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.

Then 0.5434 moles of nitrogen dioxides will give:

$\frac{2}{3}\times 0.5434 mol=0.3623 mol$ of nitric acid.

Mass of 0.3623 moles of nitric acid :

$0.3623 mol\times 63 g/mol=22.8260 g$

Theoretical yield = 22.8260 g

Experimental yield = ?

$\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100$

$75\%=\frac{\text{Experimental yield}}{22.8260 g}$

Experimental yield of nitric acid = 17.1195 g

7 0

3 years ago

The correct electron configuration of the O2-ion is

Mnenie [13.5K]

I think it’s A sorry if i’m wrong

6 0

2 years ago