Answer:
#TEAM BOB
FOR BOB!!!!!!!
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Copy and paste to help Bob.
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FOR BOB!!!!!!!
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Copy and paste to help Bob.
We can do it together!#TEAM BOB
FOR BOB!!!!!!!
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We can do it together!
Explanation:
<u><em>Your Essay Must include:</em></u>
<u><em>Introduction:Brings the main idea,Must be atleast 3 sentences.</em></u>
<u><em>Body/Details:Supports the main Idea,Must be atleast 8 sentences.</em></u>
<u><em>Body/Details(Optional):Supports the main Idea,Must be atleast 8 sentences.</em></u>
<u><em>Conclusion:Tells a little more information.</em></u>
Answer:Effect of Catalysts on the Activation Energy. Catalysts provide a new reaction pathway in which a lower Activation energy is offered. A catalyst increases the rate of a reaction by lowering the activation energy so that more reactant molecules collide with enough energy to surmount the smaller energy barrier.
Explanation:
Your answer is in this
Answer:
0.11%
Explanation:
Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.
CH3COOH <=======================================> CH3COO⁻ + H⁺
Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻ and H⁺ is 0 respectively.
At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.
1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.
The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:
percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%