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3 years ago

A man pushes a 10kg box with a constant acceleration of 5m/s2. What force is applied to the box?

2 answers:

8 0

FORMULA

$\boxed {F = m \times a}$

F = force
m = mass
a = acceleration

Using the formula

$F = 10 \times 5$

Multiply

$\boxed {\textsf {F = 10 N}}$

Diano4ka-milaya [45]3 years ago

8 0

Depends on how long you push it.

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How come that there is a presence of cos there?

liubo4ka [24]

Answer:

Can i have more context

Explanation:

8 0

3 years ago

Un automovil transita por una curva en forma de U y recorre una distancia de 400m en 30s sin embargo su posición final está a so

pochemuha

Answer:

Definimos:

Rapidez media es igual al cociente entre la distancia recorrida y el tiempo que se tarda en recorrer esa distancia.

En este caso la distancia recorrida es 400m, y el tiempo que se tarda es 30s, entonces la rapidez media va a ser:

RM = 400m/30s = 13.33 m/s

La velocidad media por otro lado, es igual al cociente entre el desplazamiento y el tiempo necesario para desplazarse.

El desplazamiento es igual a la distancia entre la posición final y la posición inicial, que en este caso eso 40m, y el tiempo necesario sigue siendo 30s, entonces la velocidad media va a ser:

VM = 40m/30s = 1.33 m/s

8 0

3 years ago

Which equation represents mass-energy equivalence? E = m2c E = mc2 E = (mc)2 E = mc

motikmotik

Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be

$E = mc^2$

where

m = mass in kg

c = speed of light in m/s

this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle

So correct relation above will be

$E = mc^2$

4 0

3 years ago

Read 2 more answers

find the average velocity of a bicycle that starts 100km south and is 120km south of town after 0.4 hours

dusya [7]

Answer:

The average velocity is 50 km/h south

Explanation:

The average velocity of an object is its total displacement divided by

the total time taken.

That means it is the rate at which an object changes its position from

one place to another.

Average velocity is a vector quantity.

The SI unit is meters per second.

A bicycle that starts 100 km south and is 120 km south of town after

0.4 hour.

The displacement = 120 - 100 = 20 km south

The time = 0.4 hour

The average velocity = $\frac{D}{T}$ , where D is the displacement

and t is the time

The average velocity of the bicycle = $\frac{20}{0.4}=50$ km/h

<em>The average velocity is 50 km/h south</em>

If you want it in meter per second, change the kilometer to meter

and change the hour to seconds

1 km = 1000 m

1 hour = 60 × 60 = 3600 seconds

The average velocity of the bicycle = $\frac{50(1000)}{3600}=13.89$ m/s south

5 0

3 years ago

A rocket's acceleration is 6.0 m/s2. Assuming it starts at 0 m/s, how long will it take for the rocket to reach a velocity of 42

elena-s [515]

You said "<span>A rocket's acceleration is 6.0 m/s2.".

That just means that its speed increases by 6 m/s every second.
Whenever you look at it, its speed is 6 m/s faster than it was
one second earlier.

If it starts out with zero speed, then its speed is 6 m/s after 1 second,
12 m/s after 2 seconds, 18 m/s after 3 seconds . . . etc.

How long does it take to reach 42 m/s ?

Well, how many times does it have to go 6 m/s FASTER
in order to build up to 42 m/s ?

That's just (42/6) = 7 times.

Writing it correctly, with the units and everything, it looks like this:

(42 m/s) / (6 m/s</span>²)

= (42/6) (m/s) / (m/s²)

= (42/6) (m/s · s²/m)

= 7 seconds

7 0

3 years ago