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HACTEHA [7]
3 years ago
14

Se um corpo 1 está em movimento em relação a um corpo 2, e se o corpo 2 está em repouso em relação a um corpo 3, pode-se afirmar

que o corpo 1 está em movimento em relação a 3? Justifique sua resposta.
Physics
2 answers:
stealth61 [152]3 years ago
8 0
Yo habla ingles no espanol
inna [77]3 years ago
8 0

Answer:

Yo habla ingles no espanol

Explanation:

You might be interested in
1. Does the validity of the principle of conservation of momentum depend on the validity of Newton's 3rd law of motion?​
OverLord2011 [107]
I truly believe so, that’s a definite yes
8 0
3 years ago
650 N boy and a 419 N girl sit on a 150 N porch swing that is 2.0 m long. If the swing is supported by a chain at each end, what
Sergio039 [100]

The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

<h3>Principle of moments</h3>

The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.

The formula for calculating moment is given below:

  • Moment = Force × perpendicular distance from the pivot

<h3>Calculating the tension in the chains</h3>

From the principle of moments:

Let tension in chain 1 be T1 and tension in chain 2 be T2.

T1 + T2 = 150 + 650 + 419

T1 + T2 =1219

Taking all distances from chain 1,

Sum of Moments = 0

419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7

T2 = 922/17

T2 = 542.35 N

Then, T1 = 1219 - 542.35

T1 = 676.65 N

Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

Learn more about tension and moments at: brainly.com/question/187404

brainly.com/question/14303536

7 0
2 years ago
4. Uncle Harry weighs 180 pounds. What is his mass in kilograms?
MatroZZZ [7]
180 pounds (lb) converts to 81.647 kilograms (kg).
5 0
2 years ago
A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed
Nataly_w [17]

Answer: P=5573.43\ W

Explanation:

Given

Mass of the elevator is M=650\ kg\\\

Time period of ascension t=3\ s

cruising speed v=1.75\ m/s

Distance moved by elevator during this time

Suppose Elevator starts from rest

\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s

Distance moved

\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m

Gain in Potential Energy is

\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N

Average power during this period is

\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W

7 0
3 years ago
Read 2 more answers
I am Pushing down at a 20
s344n2d4d5 [400]

Answer:

hivhhhh

Explanation:

iiiiuuuujrurj

7 0
2 years ago
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