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HACTEHA [7]
3 years ago
14

Se um corpo 1 está em movimento em relação a um corpo 2, e se o corpo 2 está em repouso em relação a um corpo 3, pode-se afirmar

que o corpo 1 está em movimento em relação a 3? Justifique sua resposta.
Physics
2 answers:
stealth61 [152]3 years ago
8 0
Yo habla ingles no espanol
inna [77]3 years ago
8 0

Answer:

Yo habla ingles no espanol

Explanation:

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A 0.20 mass on a horizontal spring is pulled back a certain distance and released. The maximum speed of the mass is measured to
olga55 [171]

Answer:

d

Explanation:

Ya gon find the Kenitic Energy first

K=½mv²===> K=½×0.2×(0.2)²===> 0.1(0.04)===> 0.004

and now the replacement:

0.004=½×0.4V²====> v²=0.02===> V=0.14m/s

4 0
3 years ago
COULD SOMEONE PLS DO THESE FOR ME <br> I’LL LOVE U FOREVER AND EVER
sladkih [1.3K]
I can help you do them for yourself :)
7 0
3 years ago
:What will be the value of the refractive index of the medium? Critical angle of that medium is 30 degree
earnstyle [38]

Answer:

Let the second medium be air (n₁=1)

The refractive index n₂ of the medium where first medium is air is found (a)

(a) n₂ = 2

Explanation:

Critical angle can be defined as the angle of incidence that provides the angle of refraction of 90°.

Refractive index of a medium can be defined as a number that describes that how fast a light will travel through that medium.

Critical angle and Refractive index are related by:

\theta_{critical}= sin^{-1}(\frac{n_1}{n_2})

sin \theta_{critical}=\frac{n_1}{n_2}

To find refractive index of medium with respect to air, substitute n₁=1 (Refractive index of air is 1)

Also θ(critical)=30°

Find n₂ :

sin30= \frac{1}{n_2}\\0.5=\frac{1}{n_2}\\n_2=\frac{1}{0.5}\\n_2=2

8 0
2 years ago
A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?
choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

Using Newton's 3rd equation of motion, we have :

v^{2} - u^{2} = 2×a×s

where, v = final velocity = 25 m/s

u = initial velocity = 20 m/s

a = acceleration

s = distance traveled = 300 m

Using these values in the above equation, we get acceleration = 0.375 m/s^{2}

Using Newton's second law, we have:

F=m×a

where m = mass = 1000 kg

a= acceleration = 0.375 m/s^{2}

Putting values we have F=375 N

3 0
3 years ago
Medicine A is an effective treatment for the common cold a study was conducted to test the effectiveness of medicine A which que
Xelga [282]
According to my research I found questions with the same info with option choices and they are:

A.) How many people in the study had the flu?
 B.)  How many people were included in the study?
 C.) What was the average age of the people in the study?
 D.)  What was the most common occupation of people in the study?

Among those options the answer would be the second choice B)
8 0
3 years ago
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