Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
z=-3
Step-by-step explanation:
sin x = cos 54 = sin (90-54) = sin 46
Hence x = 46 deg
Same technique. Sin 21 = cos (5x+9) = sin (90-5x-9)
81-5x = 21
Or 5x = 60
Or x = 12 deg
hope it helps
Answer:
y = 
x + 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 2x + 2 ← is in slope- intercept form
with slope m = - 2
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
=
The line crosses the y- axis at (0, 1) ⇒ c = 1 , then
y = x + 1 ← equation of perpendicular line
Attach an image of the two triangles on a cartesian plane
