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Gnesinka [82]
3 years ago
8

Describe how a plant meets the basic challenges of life???

Chemistry
1 answer:
Alinara [238K]3 years ago
7 0
It can grow, reproduce, and produce/use energy.  Hope this helps!!!
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A city water district wants to encourage local businesses and homeowners to landscape with drought-tolerant plants. After disapp
tino4ka555 [31]

Answer:

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Explanation:

the complete explanation is found in the attachment

3 0
3 years ago
. The kidneys are _______________ to the liver.
m_a_m_a [10]
I’d say posterior because the right kidney is slightly above where the liver is
7 0
3 years ago
A student has a sample of 1.33 moles of fluorine gas that is contained in a 23.3 L container at 314 K. What is the pressure of t
Gelneren [198K]

1.4715 atm is the pressure of the sample 1.33 moles of fluorine gas that is contained in a 23.3 L container at 314 K.

What is an ideal equation?

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas. The terms are: p = pressure, in pascals (Pa).

Given data:

Volume (V) = 23.3 L

Number of mole (n) = 1.33 moles

Temperature (T) = 314 K

Gas constant (R) = 0.821 atm.L/Kmol

Pressure (P) =?

The pressure inside the container can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 23.3 L = 1.33 moles × 0.0821 ×314 K

P = 1.4715 atm

Therefore, the pressure of the sample is 1.4715 atm.

Learn more about the ideal gas equation:

brainly.com/question/23826793

SPJ1

4 0
2 years ago
Help please it’s confusing to me
Colt1911 [192]

Answer:

B, H, E, G, C, D, A, F

Explanation:

The ones closest to the bottom are the oldest

6 0
2 years ago
Q #13 How many moles of MgCl2 are there in 350. g of compound?
Vaselesa [24]

<u>Answer:</u>

3.67 moles

<u>Step-by-step explanation:</u>

We need to find out the number of MgCl_2 moles present in 350 grams of a compound.

Molar mass of Mg = 24.305

Molar mass of Cl_2 = 35.453

So, one mole of MgCl_2 = 24.305 + (35.453 * 2) = 95.211g

1 Mole in 1 molecule of MgCl_2 = \frac{1}{95.211} = 0.0105

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

= 3.67 moles



8 0
3 years ago
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