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kkurt [141]
3 years ago
11

When 25mL of 0.30M solution is diluted to 50 m L , the new concentration is:

Chemistry
2 answers:
Alona [7]3 years ago
4 0

Answer: 0.15M

Explanation:

The expression used will be :

M_1V_1=M_2V_2

where,

M_1 = concentration of stock solution = 0.30 M

M_2 = concentration of dilute solution = ?

V_1 = volume of stock solution = 25 ml

V_2 = volume of dilute solution= 50 ml

Now put all the given values in the above law, we get :

(0.30M\times 25ml=(M_2\times 50ml)

By solving the terms, we get :

M_2=0.15M

Therefore, the concentration of new solution will be 0.15 M.

Citrus2011 [14]3 years ago
3 0
The first option i hope this helps

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What does the pKa of the conjugate acid of a base have to be to remove a hydrogen from water (pKa = 15.7) so that the ratio of h
Inga [223]

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Explanation:

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K_a=\frac{100}{1} =100

Now, we determine the equivalent pKa

pKa = -log[ka]

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15.7             -2

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3 years ago
In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?
IRINA_888 [86]
2 C_{6}H_{6}  +  15O_{2} ----->\ \textgreater \  12CO_{2}  +  6H_{2}O&#10;&#10;&#10;

mol of benzene =  \frac{mass}{Mr}
                                = \frac{10.47g}{(6 * 12) (6 * 1) g/mol}
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mol of oxygen: 
                 ratio of C_{6} H_{6} :  O_{2}
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                 =  1 : 7.5

: . mol of O_{2} = 0.134mol * 7.5
                                         = 1.01 mol

Mass of Oxygen = mol * Mr
                           = 1.01 mol * (16*2) g/mol
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Note: Mr is molar mass
8 0
3 years ago
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