Answer:
sure
Step-by-step explanation:
Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
The average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
<h3>What is the Average Rate of Change of a Function?</h3>
Average rate of change = .
Given the function, ,
The average rate of change using the intervals of, x = 2 to x = 6 would be solved as shown below:
a = 2
b = 6
f(a) = = 34
f(b) = = 754
Average rate of change =
Average rate of change = 180
Therefore, the average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
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