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yaroslaw [1]
3 years ago
8

Write the set of all real numbers greater than 19 and less than 32 in set-builder notation.

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer: {xI x ∈ R, 19 < x < 32}

Step-by-step explanation:

This notation is:

{xI condition1, condition2, ...}

The first condition is:

From what set we take the values of x?

From the set of real numbers.

x ∈ R

The other conditions are the limitations that we have for x, in this case:

19 < x < 32

Then we can write this as:

{xI x ∈ R, 19 < x < 32}

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olya-2409 [2.1K]
16/8= 2
2 is a whole number
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3 years ago
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Which of the following is not a danger of credit cards?
Alekssandra [29.7K]
It’s either b or d. Hope this helps! :)
7 0
3 years ago
Someone help me please?
jeka57 [31]

The Answer

LCD = 12

Equivalent Fractions with the LCD

2/3 = 8/12

3/4 = 9/12

1/2 = 6/12

Solution:

Rewriting input as fractions if necessary:

2/3, 3/4, 1/2

For the denominators (3, 4, 2) the least common multiple (LCM) is 12.

LCM(3, 4, 2)

Therefore, the least common denominator (LCD) is 12.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

2/3 = 2/3 × 4/4 = 8/12

3/4 = 3/4 × 3/3 = 9/12

1/2 = 1/2 × 6/6 = 6/12

Hope This Was Helpful :D

6 0
3 years ago
Please can anyone send a question in law of indices I really need it now​
DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

(9^p)(27^q)=3^n\\

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

(9^p)(27^q)=3^n\\\\

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

(3^2)^p(3^3)^q=3^n\\

now we multiply p with 2 and

multiply q with 3 respectively,

(3^{2p})(3^{3q})=3^n\\

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

3^{2p+3q}=3^n\\

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

2p+3q=n\\

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0
3 years ago
Help me with this one​
Alex

Answer: IM pretty sure its A

Step-by-step explanation: Thanks for being Brain member help.

6 0
3 years ago
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