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3 years ago

The period of a ripple on a lake is half a second. what is the frequency of the wave

Chemistry

1 answer:

Nataly_w [17]3 years ago

7 0

Answer:

2 Hertz

Explanation:

The frequency would be 2 Hertz.

The frequency of a wave is defined as the rate at which the particles of a medium vibrates when the wave is passed through it while the period of a wave is the time it takes the particles to make a complete cycle of vibration.

The frequency of a wave is inversely related to its period and is defined by the following equation:

f = 1/t, where f is the frequency (in hertz) and t is the period (in seconds).

Hence, if the period of a ripple is 1/2 or 0.5 seconds, the frequency becomes;

f = 1/0.5 = 2 Hertz

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Explanation :

First we have to calculate the mole of $PbCrO_4$ .

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Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

$\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g$

Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

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3 years ago

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Answer:

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