Cl-35, as the atomic mass of Chlorine (35.45) is closer to the number 35 than to the number 37. A higher abundance of CL-35 isotope would have caused the atomic number (which is an average of the values of all isotopes of a substances taking relative abundance into consideration) to decrease from 36, which would appear to be the average.
Answer:
The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE
Explanation:
Feb 16, 2012 ... How do you convert ethane to ethanoic acid? (with equation please). First you chlorinate it in presence of light. C2H6 + Cl2 ---hv -> C2H5Cl + ...
Preparation of ethanoic acid from ethane This free online course covers the preparation of ethanoic acid from ethane. The Contents tab displays all the lessons ...
he formation of the aldehyde is shown by the simplified equation: ... Note: The equation for the conversion of ethanol to ethanoic acid is worked out in detail ... Starting from ethanenitrile, you would therefore get a solution containing ethanoate ... Mar 3, 2012 ... As well as using a normal type of molecular formula to describe an organic .... In ethane the carbon atoms have the maximum number of hydrogen atoms bonded .... e.g. ethanoic acid and ethanol will produce ethyl ethanoate,.
When an electron moves from a higher energy shell to a lower one, energy in the form of light, more specifically a wavelength of a photon is released.
Answer:
V₂ ≈416.7 mL
Explanation:
This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.
where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.
The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,
- V₁= 600 mL
- T₁= 360 K
- T₂= 250 K
Substitute the values into the formula.
- 600 mL /360 K = V₂ / 250 K
Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.
- 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
- 250 K * 600 mL/360 K = V₂
The units of Kelvin cancel, so we are left with the units of mL.
- 250 * 600 mL/360=V₂
- 416.666666667 mL= V₂
Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.
The volume of the balloon at 250 K is approximately 416.7 milliliters.
