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KiRa [710]
3 years ago
15

Why does a car slide when it rolls on an icy patch on a road

Chemistry
1 answer:
Katarina [22]3 years ago
7 0

The car slides when it rolls on an icy patch on a rod because of the loss of traction.If you drive carelessly ,your're going to skid . Braking can not only trigger this skid,it will make it worse.

You might be interested in
How many moles of argon are contained in 58 L of At at STP?
Harman [31]

Answer:

n = 2.58 mol

Explanation:

Given data:

Number of moles of argon = ?

Volume occupy = 58 L

Temperature = 273.15 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × 58 L = n × 0.0821 atm.L/ mol.K × 273.15 K

58 atm.L = n × 22.43 atm.L/ mol.

n = 58 atm.L / 22.43 atm.L/ mol

n = 2.58 mol

8 0
3 years ago
What is the balance equation for
murzikaleks [220]

1st one

2_2_2

2nd one

3_1_1_3

i looked it up

7 0
3 years ago
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
Lunna [17]

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

7 0
3 years ago
1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
dlinn [17]

Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L

Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol

Substitute these values into equation 4

P = (46/2)(0.082×298)/3

P = (23×0.082×298)/3

P = 187.34 atm

3 0
3 years ago
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