Question

Each year a company selects a number of employees for a management training program. On average, 60 percent of those sent complete the program. Out of the 27 people sent, what is the probability that exactly 8 complete the program?

Answer 1

Answer:

the probability that exactly 8 complete the program is 0.001025

Explanation:

given information:

60 % of those sent complete the program, p = 0.6

the total of people being sent, n = 27

exactly 8 complete the program, x = 8

to find the probability, we can use the following formula

$P(X=x)=\left[\begin{array}{ccc}n\\x\\\end{array}\right] p^{x} (1-p)^{n-x}$

$P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (1-0.6)^{27-8}$

$P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (0.4)^{19}$

                = 0.001025