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3 years ago

2. What happens to the reaction rate if a catalyst is added?

Chemistry

2 answers:

Ghella [55]3 years ago

6 0

Answer:

A catalyst speeds up a chemical reaction

Explanation:

It increases the reaction rate by lowering the activation energy for a reaction.

mrs_skeptik [129]3 years ago

6 0

It will speed up the chemical reaction.

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explain observation made when anhydrous calcium chloride and anhydrous copper (ii) sulphate are separately exposed to the atmosp

Burka [1]

Answer:

Anhydrous calcium chloride dissolves and becomes liquid

Anhydrous copper (ii) sulphate will produce crystal particles

Explanation:

Anhydrous calcium chloride is deliquescent and hence when it is exposed to air, it absorbs water from air. After absorbing water, it dissolves and after some time a pool of clear liquid appears.

Anhydrous copper (ii) sulphate will form crystal structures and the following reaction will takes place

CuSO4 + 5 H20 --> CuSO4.5H2O

6 0

3 years ago

When two or more substances are physically combined the result is a:.

sp2606 [1]

Answer:

I think it is called a Mixture

Explanation:

Sorry if it is wrong

5 0

3 years ago

Why do we study properties of matter

Evgesh-ka [11]

Answer:

The properties of matter include any traits that can be measured, such as an object's density, color, mass, volume, length, malleability, melting point, hardness, odor, temperature, and more. We need to study all these traits since every single object around us, including us, is made of matter. Without matter we wouldn't exist; it would be infinite darkness everywhere.

8 0

3 years ago

Molten zinc chloride can be electrolysed.

Crank

Answer: The products of electrolysis are Zn(l) and $Cl_2$ gas

Explanation:

Electrolysis of a subastance is breaking it into its constituents by the action of electrical current.

In the electrolysis of molten zinc chloride, zinc metal is produced at the cathode which is a negative electrode and chlorine gas produces as the anode which is a positive electrode.

$ZnCl_2(l)\rightarrow Zn^{2+}+2Cl^-$

At anode : $2Cl^-(l)\rightarrow 2e^-+Cl_2(g)$

At cathode : $Zn^{2+}(l)+2e^-\rightarrow Zn(l)$

5 0

3 years ago

Please help

Crank

Explanation:

Hello, let's observe the given data first. The data says The conc of magnesium chloride solution is 0.117 mol/L that means in one litre solution 0.117 mole MgCl2 are present. but we have to find the moles of magnesium chloride, magnesium ions & chloride ions in 16.4 mL solution.

$\sf \: 1 \: litre \: solution \rightarrow 0.117 \: mole \: MgCl_2$

$\sf \: 16.4 \: millitre \: solution \rightarrow 0.117 \times \frac{16.4}{ {10}^{3} } \: mole \: MgCl_2 \\ \boxed{\sf 1.91 \times {10}^{ - 3} \: mole \: MgCl_2}$

Now 16.4 ml solution contains 1.91× 10-³ magnesium chloride.

Before finding the amount of ions in solution let's have a look at dissociation of magnesium chloride.

$MgCl_2 \rightarrow Mg^{2+} + 2Cl^{-}$

<em>One mole of Magnesium chloride produces 1 mole of magnesium & 2 mole of chloride ions.</em>

Hence 1.91× 10-³ moles of magnesium chloride will produce 1.91 × 10-³ moles of magnesium ion & 3.82 × 10-³ moles of chloride ions.

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3 0

2 years ago