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egoroff_w [7]
3 years ago
14

How much work does the charge escalator do to move 2.30 μC of charge from the negative terminal to the positive terminal of a 3.

00 V battery?
Physics
1 answer:
loris [4]3 years ago
6 0

Answer:

6.9\times 10^{-6} J

Explanation:

We are given that

Charge=q=2.3\mu C=2.3\times 10^{-6} C

1\mu C=10^{-6} C

Potential difference=V=3 V

We know that

Work done=V\times q

Using the formula

Work done by charge to move from the negative terminal to the positive terminal of battery=2.3\times 10^{-6}\times 3 J

Work done by charge to move from the negative terminal to the positive terminal of battery=6.9\times 10^{-6} J

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lightning is actually an enormous display of the concept of A.chemical heating B.solar energy C.magnetism D.grounding
allsm [11]

Answer:

D) Grounding

Explanation:

The potential difference between cloud and ground leads to ionization of the atmosphere and resulting conduction through the air often to ground (although it can be between clouds at different potentials. I would say grounding, like the spark when you touch a hot battery terminal to ground on a car.

5 0
3 years ago
Answer this please nowww
Viefleur [7K]
(3) The frictional force exerted by the floor on the box
4 0
3 years ago
34. A train, starting from rest, accelerates along the platform at a uniform rate of 0.6 m/s2. A passenger standing on the platf
ira [324]

Answer:

4.08 s

Explanation:

Let the passenger took "t" time to catch the train

so in this case the total distance moved by the train + 5 m = total distance moved by the passenger

so we will have

distance moved by train is given as

d_1 = \frac{1}{2}(0.6) t^2

also the distance moved by passenger

d_2 = \frac{1}{2}(1.2) t^2

so we will have

d_1 + 5 = d_2

0.3 t^2 + 5 = 0.6 t^2

0.3 t^2 = 5

t = 4.08 s

3 0
3 years ago
Why would companies want their sunscreen to absorb nearly all of the UV light?
miskamm [114]

Answer:

Sunscreen is like a shield, you would want a better shield to protect you than a weak one so companies try to make their sunscreen better than the rest.

4 0
3 years ago
Read 2 more answers
Two 0.2304 cm x 0.2304 cm square aluminum electrodes, spaced 0.5974 mm apart are connected to a 61 V battery. What is the charge
Arisa [49]

Answer:

The charge on each plate is 0.0048 nC

Explanation:

for the distance between the plates d and given the area of plates, A, and ε = 8.85×10^-12 C^2/N.m^2, the capacitance of the plates is given by:

C = (A×ε)/d

   =[(0.2304×10^-2)(0.2304×10^-2)×(8.85×10^-12))/(0.5974×10^-3)

   = 7.86×10^-14 F

then if the plates are connected to a battery of voltage V = 61 V, the charge on the plates is given by:

q = C×V

   = (7.86×10^-14)×(61)

   = 4.80×10^-14 C

   ≈ 0.0048 nC

Therefore, the charge on each plate is 0.0048 nC.

3 0
3 years ago
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