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egoroff_w [7]
3 years ago
14

How much work does the charge escalator do to move 2.30 μC of charge from the negative terminal to the positive terminal of a 3.

00 V battery?
Physics
1 answer:
loris [4]3 years ago
6 0

Answer:

6.9\times 10^{-6} J

Explanation:

We are given that

Charge=q=2.3\mu C=2.3\times 10^{-6} C

1\mu C=10^{-6} C

Potential difference=V=3 V

We know that

Work done=V\times q

Using the formula

Work done by charge to move from the negative terminal to the positive terminal of battery=2.3\times 10^{-6}\times 3 J

Work done by charge to move from the negative terminal to the positive terminal of battery=6.9\times 10^{-6} J

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A sound from a source has an intensity of 270 db when it is 1 m from the source. what is the intensity of the sound when it is 3
Lina20 [59]
Sound intensity is inversely proportional to the square of the distance between the source and the receiver.
That is 
I = k/r^2
 where
 k = constant
 r = radius

When r=1,  the intensity is I₁ = k/1 = k
When r=3, the intensity I₂ = k/3² = k/9
Therefore
 I₂ = I₁ /9

In decibels,
I = 10 log₁₀(I/I₀)
where I₀ = reference intensity

When r=1,
10 log₁₀ (I₁/I₀) = 270

When r =3,
10 log₁₀ (I₂/I₀) = 10 log₁₀ [(I₂/I₁)*(I₁/I₀)]
                     = 10 log₁₀ [(1/9)*(I₁/I₀)]
                     = 10 log₁₀(1/9) + 270
                     = 260.5

Answer: 260.5 dB (nearest tenth)
4 0
3 years ago
Based on the data you found, about how many of the 100 aliens would become thin if the temperature were 35°C?
Kruka [31]
None of them would.
I found no data.
5 0
3 years ago
An electric field of 710,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of
Anni [7]

Answer:

The magnitude of force is 4.26\times 10^{- 6} N

Solution:

As per the question:

The strength of Electric field due west at a certain point, \vec{E_{w}} = 710,000 N/C

Charge, Q = - 6 C

Now, the force acting on the charge Q in the electric field is given by:

\vec{F} = Q\vec{E_{w}}

\vec{F} = -6\times 710,000 = - 4.26\times 10^{- 6} N

Here, the negative sign indicates that the force acting is opposite in direction.

5 0
3 years ago
Gold is used to make a super thin layer on the visors of astronauts' helmets because of which property in particular?
denis-greek [22]

Answer: C. good reflector of heat

Explanation:

In space, sunlight transfers heat by radiation to objects and bodies and this includes satellites and astronauts. In addition, although the peak of the sun's emission is in the visible region of the electromagnetic spectrum, a part is also emitted in infrared (transferring thermal energy or heat) and ultraviolet (especially in the upper part of the Earth's atmosphere).

That is why in space missions, objects and many satellites are covered by thin layers or sheets that reflect this thermal energy and thus avoid damaging the equipment due to high temperatures.

In this sense, among the reflective materials used are aluminum, silver, copper and gold; the latter being the most used because it does not corrode or oxidize (unlike silver and copper) and is more malleable than aluminum.

On the other hand, <u>astronauts are also vulnerable to the effects of infrared radiation, especially their eyes</u>, since the human eye has no receptors in the infrared spectrum. <u>That is why the astronaut's helmet visor is covered with a thin layer of gold to avoid the dangerous effects of solar radiation.</u>

4 0
4 years ago
A 42 N net force is applied to a box which slides horizontally across a floor for 9.0
Rufina [12.5K]

Answer:

The Amount of work is done on the box by the net force is 378 Joules.

Explanation:

Given:

A 42 N net force is applied to a box which slides horizontally across a floor.

Force = 42 N

Force applied for a displacement of 9.0 m

Displacement = 9.0 m

To Find:

Amount of work is done on the box by the net force = ?

i.e Work = ?

Solution:

When a force causes a object to move, work is being done on the object by the force. Work is the measure of energy transfer when a force (F) moves an object through a distance (d).

Formula is given by

Work=Force\times Displacement

Substituting the given values we get

∴ Work = 42 × 9.0

∴ Work = 378 N-m

or

∴ Work = 378 Joules

The Amount of work is done on the box by the net force is 378 Joules.

8 0
4 years ago
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