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bagirrra123 [75]
3 years ago
9

Mason is a veterinarian. He is using a tiny camera, passed through a small incision, to closely examine a joint disorder. Which

diagnostic procedure is he using?
Biology
1 answer:
Mekhanik [1.2K]3 years ago
7 0
He is using an arthroscope. Which is use to examine a joint. 

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Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of
Elodia [21]

Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

5 0
3 years ago
Read 2 more answers
Imagine a species with three loci thought to be on the same chromosome. The recombination rate between locus A and locus B is 35
Vesnalui [34]

Answer:

<h2>Recombination rate or recombination frequency between locus A and locus C is either 2% or 50%. </h2>

Explanation:

As given,

Recombination frequency between locus A and B is 35%, means that the distance between A and B is 35 cM.

Recombination frequency between locus B and C is 33% , means the distance between B and C is 33 cM.

Therefore, if the locus C is present between A and B, then the recombination frequency between A and C would be 2%

A-----C ----------B

A---C= 2%

A----B= 35%

B---C= 33%

So, here the recombination frequency between A and C is 2%, means their distance is 2 cM.

If the locus C is as,   A---35---B--33----C ;   A-----B------C

A-----B= 35%

B------C= 33%

A-----C= 33+35= 68%

As rule, maximum frequency can not exceed 50%, as here the Recombination frequency between A and C = 50%.

4 0
3 years ago
Environmental science includes elements of other related science. Give two examples of related sciences
ehidna [41]

Answer:

may be they are history and geography

8 0
3 years ago
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Explain why habitats with high biodiversity tends to contain narrow ecological niches and white habitats?
alexdok [17]

Answer:

because they reduce interspecific competition

Explanation:

Narrower niches are known to be more specific and limited compared to broader niches, which are generally less specific and less limited. The species that live in broad niches are named generalists because they are able to withstand different conditions. A narrow niche is often correlated with reduced overlap and thus tends to reduce interspecific competition. For example, coral reefs consist of a wide variety of species (including anemones, sea sponges, sea fans, brain corals, etc) which have narrow niches, thus showing high biodiversity.

6 0
3 years ago
True or False? Every time you speed up, you are experiencing acceleration.
Alecsey [184]
True...................................
7 0
4 years ago
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