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3 years ago

Why can some electric appliances be immersed in water without damage?

Physics

2 answers:

Ira Lisetskai [31]3 years ago

6 0

I say that because it's the most likely thing that l wil pick

butalik [34]3 years ago

6 0

Answer:

The heating element is sealed and the control is in the detachable probe.

Explanation:

The electrical system of those appliances has been sealed (or properly insulated) so that when immersed in water, no water can get to the electrical components. This is reduces drastically the quantity of water that flow into the electrical parts.

Note that during the construction of these type of appliances, the probability of being immersed in water has been taken into consideration. Thus, they can be immersed in water without damage.

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4. If you were an astronaut on the Moon, what would you experience? What would you see from your perspective?

hjlf

an astronaut on the Moon could experience zero gravity, and would see stars and Earth.

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3 years ago

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The graph below shows the relationship between speed and time for two objects, A and B. Compare with the acceleration of object

kolbaska11 [484]

Answer:

A) greater

Explanation:

acceleration is calculated by dividing velocity over time..so by calculating, you find acceleration of A is greater than that of B

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a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro

finlep [7]

Answer:

$\theta=53.13^o$

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

$V_x=V_{ox}=V_ocos\theta$

$V_y=V_{oy}-gt=V_osin\theta-gt$

$x=V_{ox}t$

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}$

$\displaystyle y_{max}=\frac{V_{oy}^2}{2g}$

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

$x_{max}=3y_{max}$

$\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}$

Using the formulas for $V_{ox}, V_{oy}:$

$\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}$

Simplifying

$4cos\theta sin\theta=3sin^2\theta$

Dividing by $sin\theta$

$4cos\theta=3sin\theta$

Rearranging

$tan\theta=\frac{4}{3}$

$\theta=arctan\frac{4}{3}$

$\theta=53.13^o$

4 0

3 years ago

12345 [234]

The similarity is that they both are types of bonds in molecules.
Ionic bonds are between a metal and a nonmetal.
Covalent bonds are between two nonmetals.

8 0

3 years ago

A train moves at constant velocity of 50km/h. how far will it move in 0.5h?

Kobotan [32]

The formula for getting the distance will be distance = speed x time
                                                                               D = S x T
   speed or velocity = 50km/h
   time = 0.5 h
the equation will be done directly because it's already in it's SI units
            distance = 50km/h x 0.5h
            hour cancels hour and the equation remains = 50km x 0.5
                               Ans = 25 km
the train will move 25 km far in 0.5h

7 0

3 years ago