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lora16 [44]
3 years ago
14

Dois carros, a e b, móveis se em uma estrada retilínea com volocidade constante,vª =20m/s e v=18 m/s , respectivamente. O carro

A ,está, inicialmente, 500m atrás do carro B . Quanto tempo o carro A levará para alcançar o carro B?
Physics
1 answer:
LekaFEV [45]3 years ago
4 0
I just need some points
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This same car gets pulled over for speeding, and goes from 68 m/s to 0 m/s in 14
Harrizon [31]

Answer:

the acceleration of the car is -4.9m/s2.

the direction is opposite to the actual direction, since the acceleration is negative.

3 0
2 years ago
How far can a person run in 13.22 minutes if he or she runs at an average speed of 12.33 km/hr?
Alenkinab [10]

Answer:

2.72 km

Explanation:

(12.33 km)/ 1 hr * (1 hr)/ 60 min

0.2055 km/ min

distance=rate * time (assuming v is constant,

a=0)

(0.2055 km/ min)*(13.22 min)

2.72 km OR 2716.71 m

4 0
3 years ago
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If you jog at a speed of 1.5m/s for 20 seconds how far di you travel
Harlamova29_29 [7]

Answer: 30m

Explanation:

Given:

Speed: 1.5m/s

Time: 20 seconds

Distance = speed × time

Distance = 1.5 × 20

= 30m

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3 0
2 years ago
Megan was doing time trials on her bike around a 400m horizontal track. She took 32 seconds to travel 400m. What was her average
Mars2501 [29]
To find average speed, we divide the distance of travel (in this case, 400 metres) by the time she took, 32 seconds.  Therefore: 12.5 seconds is her average speed.
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2 years ago
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A person weighing 785 newtons on the surface of Earth would weigh 298 newtons on the surface of Mars.
rodikova [14]

Answer:

The gravitational field strength on the surface of Mars = 3.72 m/s²

Explanation:

Gravitational Field Strength: This can be defined as the force per unit mass which is exerted at that point. its direction is the force exerted on a mass in a gravitational field. The S.I unit of gravitational field strength is m/s²

Mathematically, Gravitational field is represented as,

g = F/m ..................... Equation 1.

m = F/g ..................... Equation 2.

Where g = gravitational Field Strength, F = force on the mass, m = mass of the body.

From the question,

Note: That The mass of the object is constant both on the surface of the earth and on the surface of Mars.

On the Surface of the earth,

Given: F = 785 N, g = 9.8 m/s²

Substituting this values into equation 2,

m = 785/9.8

m = 80.10 kg.

On the surface of Mars.

Given: m = 80.10 kg, F = 298.

Substituting into equation 2

g = 298/80.1

g = 3.72 m/s²

Thus the gravitational field strength on the surface of Mars = 3.72 m/s²

3 0
3 years ago
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