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frez [133]
3 years ago
14

A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir

ection at 14.2 cm/s. After the collision, the 13.5 g marble moves to the right at 71 cm/s. Find the velocity of the 27.0 g marble after the collision.
Physics
1 answer:
Nataly [62]3 years ago
7 0

Answer:v_1=28.4 cm/s

Explanation:

Given

mass of marble m_1=27 gm

velocity of marble u_1=56.8 cm/s \approx 0.568 m/s

mass of second marble m_2=13.5 gm

Velocity of second marble u_2=14.2 cm/s \approx 0.142 m/s

After collision 13.5 gm marble moves to the right  at i.e. v_2=71 cm/s

Conserving momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71

1533.6+191.7=27\cdot v_1+958.5

27\cdot v_1=766.8

v_1=\frac{766.8}{27}=28.4 cm/s

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